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3 years ago

What is the value of x?

Mathematics

2 answers:

vladimir1956 [14]3 years ago

6 0

Answer:

x=9

Step-by-step explanation:

Since this is an equilateral triangle, all angles are equal to (180/3) 60 degrees

<N = 60 = 7x-3

60 = 7x-3

Add 3 to each side

60+3 = 7x-3+3

63 =7x

Divide by 7

63/7 =7x/7

9 =x

Lorico [155]3 years ago

4 0

Answer:

I believe that the answer you need is x=0.42

Step-by-step explanation:

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2 years ago

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

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$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$

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2 years ago

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