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leonid [27]
3 years ago
5

in a test tube, there is 4 ML of oil and 6 ML of water. What volume percent of liquid in your test tube is oil? Show a ratio of

oil to water.
Mathematics
1 answer:
Nady [450]3 years ago
4 0
3:2, easy. 

the rest you dont need to read i just need 20 characters to "explain it well".
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X+50=278<br><br> PLease help really quick
Anon25 [30]

Answer: x= 228

x= 278-50

x=228

7 0
3 years ago
Read 2 more answers
Kiran and his cousin work during the summer for a landscaping company. Kiran's cousin has been working for the company longer, s
Marta_Voda [28]
Kiran earns $8.50 per hour.

Let x represent Kiran's pay.  He worked 23 hours last week, so his pay would be given by 23x.

Kiran's cousin is paid 30% more.  30% = 30/100 = 0.3.  We add this to the x per hour that Kiran is paid:

x + 0.3x = 1.3x

This is multiplied by 27, since Kiran's cousin works 27 hours:
27(1.3x)

This gives us the following equation:
23x + 27(1.3x) = 493.85
23x + 35.1x = 493.85
58.1x = 493.85

Divide both sides by 58.1:
58.1x/58.1 = 493.85/58.1
x = 8.5

Thus Kiran earns 8.50 per hour.
8 0
3 years ago
The population of rabbits on an island is growing exponentially. In the year 1994, the population of rabbits was 9600, and by 20
drek231 [11]

Answer:

49243

Step-by-step explanation:

Given that the population of rabbits on an island is growing exponentially.

Let the population, P=P_0e^{bt}

where, P_0 and b are constants, t=(Current year -1994) is the time in years from 1994.

In 1994, t=0, the population of rabbit, P=9600, so

9600=P_0e^{b\times 0}

So, P_0=9600

and in 2000, t=2000-1994=6 years and population of the rabbit, P=18400

18400=9600 \times e^{b\times 6} \\\\\frac{18400}{9600}=e^{b\times 6} \\\\

\ln(23/12}=6b \\\\

b = \frac{\ln{1.92}}{6} \\\\

b=0.109

On putting the value of P_0 and b, the population of the rabbit after t years from 1994 is

P=9600 \times e^{0.109\times t}

In 2009, t= 2009-1994=15 years,

So, the population of the rabbit in 2009

P=9600 \times e^{0.109\times 15}=49243

Hence, the population of the rabbit in 2009 is 49243.

7 0
3 years ago
Solve each of the following systems of equations by substitution
Delvig [45]

Answer:

1) The solution to the given equations is (3,6)

2) The solution to the given equations is (7,-1)

3) The solution to the given equations is (6,5)

Step-by-step explanation:

1) Given equations are x+y=5\hfill (1)

and x=1+y\hfill (2)

To solve the given equations by substitution method :

From equation (2) we have the value x=1+y

Substitute the value of x=1+y  in equation (1) we get

(1+y)+y=5

1+y+y=5

1+2y=5

2y=5-1

2y=4

y=\frac{4}{2}

Therefore y=2

Now substitute the value of y=2 in equation (2) we get

x=1+y

x=1+2

Therefore x=3

The solution is (3,6)

2) Given equations are 2x+3y=11\hfill (1)

and x+y=6\hfill (2)

To solve the given equations by substitution method :

From equation (2) we have the value x=6-y

Substitute the value of x=6-y  in equation (1) we get

2(6-y)+3y=11

12-2y+3y=11

y=11-12

Therefore y=-1

Now substitute the value of y=-1 in equation (2) we get

x+(-1)=6

x=6+1

Therefore x=7

The solution is (7,-1)

3) Given equations are x-y=1\hfill (1)

and 6x-7y=1\hfill (2)

To solve the given equations by substitution method :

From equation (1) we have the value x=1+y

Substitute the value of x=1+y  in equation (2) we get

6(1+y)-7y=1

6+6y-7y=1

-y=1-6

Therefore y=5

Now substitute the value of y=5 in equation (1) we get

x-5=1

x=1+5

Therefore x=6

The solution is (6,5)

8 0
3 years ago
What is the greatest common factor of ? 6^10 y^12-12x^14 +x^8 y^6
ValentinkaMS [17]

Answer:

i Think its 1

Step-by-step explanation:

8 0
3 years ago
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