For this case, the first thing we must do is define variables:
x = number of quarters
y = number of dimes
We now write the system of equations:
x + y = 28
0.25x + 0.10y = 4.05
Solving the system of equations we have:
x = 8.33
y = 19.66
Rounding:
x = 8
y = 20
Answer:
the college student has:
8 quarters
20 dimes
Answer:
y = 24
Step-by-step explanation:
3x + y = 6
Solve for y
Subtract 3x from each side
3x -3x+ y = 6-3x
y = 6-3x
Let x = -6
y = 6 -3(-6)
=6+18
=24
For equation
y = ax² +bx +c
the line of symmetry is given by
x = -b/(2a)
Filling in the given values, we have
-2 = -(-4)/(2a)
a = 4/(2(-2)) = -1
The value of "a" is -1.