Let x and y be the 2 parts of 15 ==> x + y=15 (given)
Reciprocal of x and y ==> 1/x +1/y ==> 1/x + 1/y = 3/10 (given)
Let's solve 1/x + 1/y = 3/10 . Common denominator = 10.x.y (reduce to same denominator)
==> (10y+10x)/10xy = 3xy/10xy ==> 10x+10y =3xy
But x+y = 15 , then 10x+10y =150 ==> 150=3xy and xy = 50
Now we have the sum S of the 2 parts that is S = 15 and
their Product = xy =50
Let's use the quadratic equation for S and P==> X² -SX +P =0
Or X² - 15X + 50=0, Solve for X & you will find:
The 1st part of 15 is 10 & the 2nd part is 5
The expression is given by:

So we need to find an equivalent equation for this problem. Then, we will apply some mathematical rules:
Extracting the common factor 1/4, then:

Or extracting the common factor -1/4, then:

So, comparing these solutions with the answers about, there is no any answer that matches.
You will find all of the surface area of all of the sides and add them together to find the surface area of the retangular prisim. So, what I would do is the front and back are both 54, so 108. The sides are 27, so 54. The top and bottom are 18, so 36. Add them together, and you will get 198. I hope this helps.