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IRISSAK [1]
3 years ago
10

(6-2.7h)+(-1.3j-4) ?

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
8 0

Answer:

−2.7h−1.3j+2

Step-by-step explanation:

Murljashka [212]3 years ago
5 0

Answer:

= 2 - 2.7h - 1.3j

Step-by-step explanation:

(6-2.7h)+(-1.3j-4)

we solve the question with the BODMAS

BRACKET

OF

DIVISION

MULTIPLICATION

ADDITION and

SUBTRACTION

(6-2.7h)+(-1.3j-4)

Solve the bracket first

= 6 - 2.7h - 1.3j - 4

Now we collect like terms

= 6 - 4 - 2.7h - 1.3j

= 2 - 2.7h - 1.3j

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Using the Pythagorean Theorem,
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A truck is being filled with cube-shaped packages that have side lengths of 1/4 foot. The part of the truck that is being filled
n200080 [17]

Answer:

24000 pieces.      

Step-by-step explanation:

Given:

Side lengths of cube = \frac{1}{4} \ foot

The part of the truck that is being filled is in the shape of a rectangular prism with dimensions of 8 ft x 6 1/4 ft x 7 1/2 ft.

Question asked:

What is the greatest number of packages that can fit in the truck?

Solution:

First of all we will find volume of cube, then volume of rectangular prism and then simply divide the volume of prism by volume of cube to find the greatest number of packages that can fit in the truck.

Volume\ of\ cube =a^{3}

                          =\frac{1}{4} \times\frac{1}{4}\times \frac{1}{4} =\frac{1}{64} \ cubic \ foot

                                   

Length = 8 foot, Breadth = 6\frac{1}{4} =\frac{25}{4} \ foot, Height =7\frac{1}{2} =\frac{15}{2} \ foot

Volume\ of\ rectangular\ prism =length\times breadth\times height

                                                =8\times\frac{25}{4} \times\frac{15}{2} \\=\frac{3000}{8} =375\ cubic\ foot

The greatest number of packages that can fit in the truck = Volume of prism divided by volume of cube

The greatest number of packages that can fit in the truck = \frac{375}{\frac{1}{64} } =375\times64=24000\ pieces\ of\ cube

Thus, the greatest number of packages that can fit in the truck is 24000 pieces.                                

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Step-by-step explanation:

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