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Elden [556K]
4 years ago
10

Please I need ur help

Mathematics
1 answer:
Bess [88]4 years ago
3 0

Answer:

Step-by-step explanation:

Can you write it down on a different peace of paper

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Convert 60 quarts to gallons. 60 qt = ? gal Will the converted amount have more or fewer units than the original? ​
san4es73 [151]

Answer: 15 gallons .

Step-by-step explanation:

Step 1

4 quarts = 1 gallon

therefore 60 quarts = (60 quarts x 1 gallon) / 4 quarts

= 15 gallons .

Step 2-- The converted amount which is 15  has fewer units than the original which is 60.

7 0
3 years ago
G(x) = 4x + 2
mojhsa [17]

Answer:

4x \times 2x + 4x \times 5 + 2 \times 2x + 2 \times 5 = 8x {}^{2} + 24x + 10

6 0
3 years ago
Please can some help me in this?
tino4ka555 [31]

Answer:

n = 70

Step-by-step explanation:

14 * x < 80

x = 6 won't work

14 * 6 = 84 which beyond the boundry.

14 * 5 = 70 which is less than 80 and is divisible by 14

14 * 3 = 42

70 does not have a 3 in it.

So the largest number that has 14 in it and is less than 80 is 70

5 0
3 years ago
Twins Isaac and Isaac where just born. Issac weighs 6 pounds 2 ounces and Isaiah weighs 5 pounds 4 ounces how many ounces do the
Ray Of Light [21]
182 ounces isthe answer
3 0
4 years ago
It takes 20 hours and $400 to interview a candidate, and it takes 120 hours and $3600 to train an employee. A company has less t
zavuch27 [327]
<span>Let C denote the number of candidates they interview and E the number of employees they train.
</span>
<span>If it takes 20 hours and $400 to interview a candidate, then it takes 20C hours and $400C to interview C candidates.
</span>
If <span>it takes 120 hours and $3600 to train an employee, then it takes 120E hours and $3600E to train E employees.
</span>
Company has less than <span>$95000, then 400C+3600E<95000.
</span>
Company <span>wants to spend at most 470 hours, then 20C+120E\le&#10; 470.
</span>
<span>You obtain the system of two inequalities:
</span>

\left \{ {{400C+3600E\ \textless \ 95000} \atop {20C+120E\le&#10; 470}} \right.  \\  \left \{ {{4C+36E\ \textless \ 950} \atop {C+6E\le &#10;23.5}} \right. \\ \left \{ {{4C+36E\ \textless \ 950} \atop {4C+24E\le &#10;94}} \right.
Then you can solve this system according to your demands.






3 0
3 years ago
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