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BartSMP [9]
2 years ago
10

Write an equation for the line that has a slope -8/9 and goes through the point (-7, 7)

Mathematics
2 answers:
Jobisdone [24]2 years ago
5 0

Answer:

y = (-8/9)x + 0.77777

Step-by-step explanation:

We already know the slope, so the only thing left to find is the y-intercept.

To find the y-intercept, we can <u>plug in the slope and point to the slope-intercept form equation</u> (y = mx+b, where m=slope and b=y-int.)

y   =     m *  x    + b

(7) = (-8/9)*(-7)   + b

<u>Now, just solve for b!</u>

(7) = (-8/9)*(-7)   + b

7 = 56/9 + b

7 - (56/9) = b

b = 0.777777 (repeating decimal, usually signified by a little line above the 7)

so now we just <u>plug in the slope and y-intercept we found into y = mx + b.</u>

y = mx + b

y = (-8/9)x + 0.77777

raketka [301]2 years ago
5 0

Answer:

Use the two point formula to find the equation of the line through two given points (x, y) and (X² X¹) is y-y¹/x-x² = y²-y¹/x²-x¹

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2 years ago
Mark can remember only the first 4 digits of his friend's phone number. He also knows that the number has 7 digits and that the
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Answer:

<em>19800 seconds, or 330 minutes, or 5 hours + 30 minutes</em>

Step-by-step explanation:

<u>Number Permutations</u>

We know the phone number has 7 digits, 4 of which are known by Mark. This leaves him 3 digits to guess with. We also know the last one is not zero. The number can be represented as

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(\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{8}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-3)}}}\implies \cfrac{3}{6+3}\implies \cfrac{3}{9}\implies \cfrac{1}{3}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-5=\cfrac{1}{3}(x+3)\implies y-5=\cfrac{1}{3}x+1\implies y=\cfrac{1}{3}x+6

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