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Mathematics

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-BARSIC- [3]3 years ago

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A random variable r is normally distributed with a mean of 7 and a standard deviation of 1.5. Find the value of w so that P (8.8

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Answer:

The answer is explained below

Step-by-step explanation:

Given that:

mean (μ) = 7 and standard deviation (σ) = 1.5.

The z score is used in statistic used to measure the number of standard deviation by which the raw score is above or below the mean value. It is given by:

$z=\frac{x-\mu}{\sigma}, where\ x\ is\ the \ raw\ score$

To find the Probability that x < 8.8, we first find the z score using:

$z = \frac{x-\mu}{\sigma}=\frac{8.8-7}{1.5}=1.2$

From the z tables, P(x < 8.8) = P(z < 1.2) = 0.8849 = 88.49%

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

$slope = \frac{rise}{run} = \frac{y2 - y1}{x2 - x1} \\ = \frac{ - 7 - 13}{5 - ( - 3)} \\ = \frac{ - 20}{8} \\ = \frac{ - 2 \times 10}{2 \times 4} \\ = \frac{ - 10}{4} \\ = \frac{ - 2 \times 5}{ 2 \times 2} = \frac{5}{2}$

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