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aev [14]
3 years ago
13

Fin math today PLEASE

Mathematics
1 answer:
ollegr [7]3 years ago
4 0

Answer:

1) Area:

So to find area follow the formula

a=πr^2

a=area

π= pi or 3.14 in this situation

r= radius

So we have only the diameter.

To in Find the radius you can divide the diameter by 2 and get the radius which is

84/2=42

3.14*42^2=

Area: 5538.96 ft^2

2) Circumference:

To find the circumfeence you just multiply the diameter by π or in this case 3.14.

c=πd

c= circumference  

d= diameters

3.14*84=

Circumfrence: 263.76 ft

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3 years ago
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Need help + explanation!! ^_^
Paha777 [63]
780, or C, is correct.  Since 9.75 is 1/80th of the actual measurement, we can set up an equation like this:

9.75 = 1/80x

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780 = x

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3 0
3 years ago
A quiz has 1 true-false question and 2 multiple choice questions that each have 4 answers what is the probability that someone q
Anit [1.1K]
1 true and false question = 1 / 2 chances
2 multiple choice question = 2/8
1/2 + 2/8 =
4/8 + 2/8 = 6/8.

6/8 = 3/4

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8 0
3 years ago
An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of
ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

  • The probability of the word free occurring in a spam message is,             P(F|S)=0.60
  • The probability of the word free occurring in a valid message is,             P(F|V)=0.04
  • The probability of spam messages is,

        P(S)=0.20

First let's compute the probability of valid messages:

P (V) = 1 - P(S)\\=1-0.20\\=0.80

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The probability that a message contains the word free is:

P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is spam provided that it contains free is:

P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is valid provided that it does not contain free is:

P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0
4 years ago
Como se hace el calculo de: 12 + 9a + 18b = ----- * ( ---- + 3a + ----- )
nexus9112 [7]

Answer:

3(4+3a+6b)

Step-by-step explanation:

8 0
3 years ago
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