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3 years ago

9

At a video arcade action video games usually cost $12.50. This week they are on sale for 30% off. What is the sale price of the

action video games?

2 answers:

IgorLugansk [536]3 years ago

6 0

Answer:

$8.75

Step-by-step explanation:

We have been given that at a video arcade action video games usually cost $12.50. This week they are on sale for 30% off.

The sale price of the action video-game would be 70% (100%-30%) of $12.50.

$\text{The sale price of the action video-game}=\$12.50\times \frac{70}{100}$

$\text{The sale price of the action video-game}=\$12.50\times 0.70$

$\text{The sale price of the action video-game}=\$8.75$

Therefore, the sale price of the action video game would be $8.75.

Juliette [100K]3 years ago

5 0

Answer: 8.75

Step-by-step explanation:

12.50 x 30% or .03

= 3.75

3.75 - 12.50

= 8.75

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67.5

45° would be the other angle of 2x°

180° - 45° = 135°

135/45 = 67.5°

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3 years ago

Given the function f(x) = 6x^2 −13, what is f(-3)?

Naya [18.7K]

<h3>Answer: 41</h3>

Work Shown:

f(x) = 6x^2 - 13

f(x) = 6(x)^2 - 13

f(-3) = 6(-3)^2 - 13 ... replace every x with -3; use PEMDAS to simplify

f(-3) = 6(9) - 13

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3 years ago

What is the vertical shift of the graph of the parent cosecant function to the graph of the function below?

STatiana [176]

Answer:

Option: C is the correct answer.

C. 3 units down.

Step-by-step explanation:

We know that the graph of a cosecant function has a minimum value for a upward open curve as : 1

It could be seen from the graph.

But here the minimum value of the upward open curve in the transformed function is: -2

This means that the vertical shift is given by:

-2-1=-3

This means that there is a vertical shift of 3 units down in the parent function.

4 0

3 years ago

Read 2 more answers

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0

3 years ago

In the last six months, Sonia's family used 529, 499, 651, 652, 1,163, and 310 minutes on their cell phone plan. To save money,

Tresset [83]

Answer:

They went over their goal for the last six months by 34 minutes per month.

Step-by-step explanation:

Mean of a data-set:

The mean of a data-set is the sum of all values in the data-set divided by the size of the data-set.

529, 499, 651, 652, 1,163, and 310 minutes on their cell phone plan.

The mean is:

$M = \frac{529+499+651+652+1163+310}{6} = 634$

By how many minutes did they go over their goal in the last six months?

The mean was of 634 minutes, and they wanted to keep it below 600. So

634 - 600 = 34

They went over their goal for the last six months by 34 minutes per month.

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3 years ago