In the function y-1=(4x)^2+7 , what effect does the number 4 have on the graph, as compared to the graph of y=x^2 ?
2 answers:
<span>Points (1,3) are given in the form of (x,y)
So, (x,y) = (1,3) which shows that x = 1 and y = 3 </span><span>So, y = 3x + b 3 = 3(1) + b if you would solve for b you will get </span> b= 0
The constant terms only translate the function upward or donward. Here the focus is in the coefficient that multiplies the term x^2. The effect is to stretch the graph vertically. In y=x^2, when x = 1 y =1 and when x=2 y = 4 In y=(4x)^2 , when x = 1 y = 16 and when x =2 y=16 Then the factor of stretching vertically is 16. Also you can see the transformation from the point of view of the horizontal axis. For the function y =x^2, when y is 16 x = 4, For the function y = (4x)^2, when y is 16 x = 1, For the funcion y = x^2, when y = 64 x = 8 For the function y =(4x)^2, when y = 64 x =2 Then x is multiplied by a factor of 1/4, which means that the answer is " <span>It shrinks the graph horizontally to 1/4 the original width" </span> That is why the resu
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