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kirza4 [7]
3 years ago
8

SAVE ME. Please Answer my Questions Clevers.

Mathematics
1 answer:
Vladimir [108]3 years ago
7 0

Answer:

See below

Step-by-step explanation:

Q1. if a counting number is selected at random from a set of whole number less than or equal to 20 find the probability of getting:

Counting numbers are Natural numbers: \mathbb{N}

Also, we have Whole numbers. Despite not having an official symbol, I usually denote the set as \mathbb{Z}_{\ge 0}

<u>Whole numbers less than or equal to 20</u>: A\leq 20, A \subset \mathbb{Z}_{\ge 0}  \\\implies A=\{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20\}

<u>A. Prime numbers</u>

From the set A, the prime numbers are 2, 3, 5, 7, 11, 13, 17, 19.

Once we have 21 numbers in total and 8 prime numbers, the probability is:

$P=\frac{8}{21} \approx 40\%$

<u>B. Composite numbers</u>

From the set A, the composite numbers are 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20.

Once we have 21 numbers in total and 11 composite numbers, the probability is:

$P=\frac{11}{21} \approx 52\%$

<u>C. Divisible by three</u>

From the set A, the numbers divisible by three are 3, 6, 9, 12, 15, 18.

Once we have 21 numbers in total and 6 numbers divisible by three, the probability is:

$P=\frac{6}{21} \approx 30\%$

<u>D. Square of 2</u>

From the set A, the numbers square of 2 are 0, 1, 4, 9, 16.

\sqrt{0} =0

\sqrt{1} =1

\sqrt{4} =2

\sqrt{9} =3

\sqrt{16} =4

Once we have 21 numbers in total and 5 numbers square of 2 , the probability is:

$P=\frac{5}{21} \approx 24\%$

Q2. The opposite angle of acyclic quadrilaterals is in the ratio of 2:3. Find the degree measure of each opposite angle?

Once they're opposite, they add up to 180º

2x+3x=180 \implies 5x=180 \implies x=36

The first angle is 72º

The second angle is 108º

Q3. what is the solution set of  9x-4<13x-7 (domain, x e z) ?

x \in \mathbb{Z}\\

$x>\frac{3}{4} $

$x\in \left(\frac{3}{4},\infty \right)$

Q4. if three fourth of a number is one tenths, what is the number?

$\frac{3}{4} x =\frac{1}{10} \implies 3x=\frac{4}{10}  \implies \boxed{x = \frac{2}{15}} $

Q5. which one is the equation of the line passing through the origin and having a slope 4?

y=mx+b

m: \text{slope}

b: \text{y-intercept}

B. Y= 4x

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Answer:

p =  \frac{m}{v}

Step-by-step explanation:

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2 years ago
Find the solution set for this equation M^2-4=0
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Step-by-step explanation:

Hey, there !!

Let's simply work with it,...................

Here, theequation is,

{m }^{2} - 4 = 0

or \:  {m }^{2}  = 4

or \: m  =   +  -  \sqrt{4}

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5 0
3 years ago
5) In a urea manufacturing plan, all employees work a basic week of 40 hours. Ay overtime worked during weekdays is paid for at
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Step-by-step explanation:

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Total for overtime worked on Saturday;

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Step-by-step explanation:

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) You are finally well!  But now your child is sick!  You know there have been mistakes in orders so you are on the internet t
rjkz [21]

Answer:

The doctor's dosage was not appropriate.

The right dosage is from 56.625 mg to 113.25 mg of Antibiotic to be given every 6 hour for the child with weight 25 lbs.

Step-by-step explanation:

It is given that 20 to 40 mg/kg/day is the recommended dosage.

Now, the doctor's order is 150 mg of antibiotic to be given every 6 hours. And my child weighs 25 lbs.

Now, 1 lb is equivalent to 0.453 kg.

So, my child's weight is (25 × 0.453) = 11.325 kg.

So, the doctor's order is 150 mg of antibiotic to be given every 6 hours for a child of weight 11.325 kg.

Hence, the dosage is [(150 × 4) ÷ 11.325] = 52.98 mg/kg/day.

So, this is not within the limit of 20 to 40 mg/kg/day.

Therefore, the doctor's dosage was not appropriate.

Now, let the appropriate dosage is x mg per every 6 hours for a child with weight 25 lbs i.e. 11.325 kg.

So, 20 \leq  \frac{4x}{11.325} \leq 40

⇒ 20\leq 0.3532x \leq 40

⇒ 56.625 \leq  x \leq  113.25

So, the right dosage is from 56.625 mg to 113.25 mg of antibiotic to be given every 6 hours for the child with weight 25 lbs. (Answer)

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3 years ago
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