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kirza4 [7]
3 years ago
8

SAVE ME. Please Answer my Questions Clevers.

Mathematics
1 answer:
Vladimir [108]3 years ago
7 0

Answer:

See below

Step-by-step explanation:

Q1. if a counting number is selected at random from a set of whole number less than or equal to 20 find the probability of getting:

Counting numbers are Natural numbers: \mathbb{N}

Also, we have Whole numbers. Despite not having an official symbol, I usually denote the set as \mathbb{Z}_{\ge 0}

<u>Whole numbers less than or equal to 20</u>: A\leq 20, A \subset \mathbb{Z}_{\ge 0}  \\\implies A=\{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20\}

<u>A. Prime numbers</u>

From the set A, the prime numbers are 2, 3, 5, 7, 11, 13, 17, 19.

Once we have 21 numbers in total and 8 prime numbers, the probability is:

$P=\frac{8}{21} \approx 40\%$

<u>B. Composite numbers</u>

From the set A, the composite numbers are 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20.

Once we have 21 numbers in total and 11 composite numbers, the probability is:

$P=\frac{11}{21} \approx 52\%$

<u>C. Divisible by three</u>

From the set A, the numbers divisible by three are 3, 6, 9, 12, 15, 18.

Once we have 21 numbers in total and 6 numbers divisible by three, the probability is:

$P=\frac{6}{21} \approx 30\%$

<u>D. Square of 2</u>

From the set A, the numbers square of 2 are 0, 1, 4, 9, 16.

\sqrt{0} =0

\sqrt{1} =1

\sqrt{4} =2

\sqrt{9} =3

\sqrt{16} =4

Once we have 21 numbers in total and 5 numbers square of 2 , the probability is:

$P=\frac{5}{21} \approx 24\%$

Q2. The opposite angle of acyclic quadrilaterals is in the ratio of 2:3. Find the degree measure of each opposite angle?

Once they're opposite, they add up to 180º

2x+3x=180 \implies 5x=180 \implies x=36

The first angle is 72º

The second angle is 108º

Q3. what is the solution set of  9x-4<13x-7 (domain, x e z) ?

x \in \mathbb{Z}\\

$x>\frac{3}{4} $

$x\in \left(\frac{3}{4},\infty \right)$

Q4. if three fourth of a number is one tenths, what is the number?

$\frac{3}{4} x =\frac{1}{10} \implies 3x=\frac{4}{10}  \implies \boxed{x = \frac{2}{15}} $

Q5. which one is the equation of the line passing through the origin and having a slope 4?

y=mx+b

m: \text{slope}

b: \text{y-intercept}

B. Y= 4x

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Answer:

-1

Step-by-step explanation:

The rise over run is -2 over -2.

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An icicle with a diameter of 15.5 centimeters at the top, tapers down in the shape of a cone with a length of
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Answer:

Step-by-step explanation:

Note: I will leave the answers as fraction and in terms of pi unless the question states rounding conditions to ensure maximum precision.

From the question, we can tell it is a inversed-cone (upside down)

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We know the density of ice is 0.93 grams per 1cm^{3}

1cm^{3} =0.93g\\\frac{168175\pi }{24}  cm^{3} =0.93(\frac{168175\pi }{24} )\\= 20473 g(Nearest Gram)

b) After 1 hour, we know that the new radius = 7.75cm - 0.35cm = 7.4cm

and the new length, h = 350cm - 15cm = 335cm

Now we will find the volume of this newly-shaped cone.

Volume of cone = \pi (7.4)^{2} \frac{335}{3} \\= \frac{91723\pi }{15} cm^{3}

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c) Lets take the bucket as a round cylinder.

Given radius of bucket, r = 12.5cm (Half of Diameter) and h , height = 30cm.

Volume of cylinder = \pi r^{2} h\\=\pi (12.5)^{2} (30)\\=\frac{9375\pi }{2} cm^{3}

To overflow the bucket, the volume of ice melted must be more than the bucket volume.

Volume of ice melted after 5 hours = 5(\frac{35697\pi }{40} )\\=\frac{35697\pi }{8} cm^{3}

See, from here of course you are unable to tell whether the bucket will overflow as all are in fractions, but fret not, we can just find the difference.

Volume of bucket - Volume of ice melted after 5 hours

= \frac{9375\pi }{2} -\frac{35697\pi }{8 } \\=\frac{1803\pi }{8}cm^{3}

from we can see the bucket can still hold more melted ice even after 5 hours therefore it will not overflow.

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You mught want to check over it so you will be able to solve it for yourself the next time you have this question. 

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