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Fudgin [204]
3 years ago
10

Help me please !!!!!!!!!!!!!!!

Mathematics
1 answer:
Vitek1552 [10]3 years ago
4 0

16 units. Start from -2 and count up to 14. Basically -2+2+2+2+2+2+2+2+2+2 since the scale is by 2

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(HELP!)
denis-greek [22]

Let X be the random variable denoting the number of girls that are born. Then X has a binomial distribution on n=125 babies and probability of getting a girl p=0.5. The probability we want is

\mathbb P(X\ge60)=\displaystyle\sum_{x=60}^{125}\binom{125}x0.5^{125-x}0.5^x\approx0.704=70.4\%

7 0
3 years ago
Read 2 more answers
Write an algebraic expression for the given quantity. Let x represent the unknown value.
Lelechka [254]

Answer:

Step-by-step explanation:

There is no equal sign.

1/2 x - 5*x

is all there is.

7 0
2 years ago
The two dot plots show the number of miles ran by 14 students at the beginning and at the end of the school year compare each me
Naddika [18.5K]

The two dot plots are missing, so i have attached it.

Answer:

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

Step-by-step explanation:

From the attached image, we are told to compare the means for each plot to the nearest tenth.

Mean = Σx/n

Now, from the image, total number of miles run by the 14 students at the beginning of the school year is;

(1 × 7) + (2 × 8) + (4 × 9) + (4 × 10) + (2 × 11) + (1 × 12) = 133

Mean of miles run at the beginning of the school year = 133/14 = 9.5 miles

Again, from the table, total miles run at the end of the school year = (2 × 8) + (2 × 9) + (4 × 10) + (3 × 11) + (3 × 12) = 143

Mean of miles run at the end of the school year = 143/14 = 10.2 miles

Thus;

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

5 0
3 years ago
Find the area of the figure. Round to the nearest hundredth if necessary
ki77a [65]
The area of the figure :)

8 0
3 years ago
Read 2 more answers
Which is the equation of a parabola with a directrix at y = −3 and a focus at (5, 3)? y = one twelfth(x − 5^)2
ankoles [38]

The equation of a parabola with a directrix at y = -3 and a focus at (5 , 3) is y = one twelfth (x - 5)² ⇒ 1st answer

Step-by-step explanation:

The form of the equation of the parabola is  (x - h)² = 4p(y - k), where

  • The vertex of the parabola is (h , k)
  • The focus is (h , k + p)
  • The directrix is at y = k - p  

∵ The focus of the parabola is at (5 , 3)

- Compare it with the 2nd rule above

∴ h = 5

∴ k + p = 3 ⇒ (1)

∵ The directrix is at y = -3

- By using the 3rd rule above

∴ k - p = -3 ⇒ (2)

Solve the system of equations to find k and p

Add equations (1) and (2) to eliminate p

∴ 2k = 0

- Divide both sides by 2

∴ k = 0

- Substitute the value of k in equation (1) to find p

∵ 0 + p = 3

∴ p = 3

Substitute the values of h , k , and p in the form of the equation above

∵ (x - 5)² = 4(3)(y - 0)

∴ (x - 5)² = 12 y

- Divide both sides by 12

∴ \frac{1}{12} (x - 5)² = y

- Switch the two sides

∴ y =  \frac{1}{12} (x - 5)²

The equation of a parabola with a directrix at y = -3 and a focus at (5 , 3) is y =  \frac{1}{12} (x - 5)²

Learn more:

you can learn more about the quadratic equations in brainly.com/question/8054589

#LearnwithBrainly

8 0
3 years ago
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