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3 years ago

Help me please !!!!!!!!!!!!!!!

Mathematics

1 answer:

Vitek1552 [10]3 years ago

4 0

16 units. Start from -2 and count up to 14. Basically -2+2+2+2+2+2+2+2+2+2 since the scale is by 2

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Describe the Glide Reflection from the preimage triangle in Black to the image triangle and red

cestrela7 [59]

We want the final coordinate of K to become (-3,1). If you reflect across the y-axis, you transform

$(x,y)\mapsto(-x,y)$

So, we need to move K to (3,1), and then reflect it across the y-axis. Since K starts at (-1,4), we have to move it 4 units to the right and 3 units down.

4 0

3 years ago

Describe the term linear pair, and give an example from the diagram.

Burka [1]

Answer/Step-by-step explanation:

A linear pair is formed when two straight lines intersect to form two angles that are adjacent to each other and are on a straight line. The sum of both adjacent angles equals 180°.

From the diagram given, examples of linear pair are:

<FEG and <GEN

<CDE and <ADC

These are some of the few examples we can see in the given diagram that are linear pairs.

6 0

3 years ago

Integral of cosecx dx =log|tanx/2| show that.

Pie

ANSWER:

Let t = logtan[x/2]

⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx

⇒dt = 1/2 cos² x/2 × cot x/2dx

⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx

⇒dt = 1/2 cosx/2 / sin x/2 dx

⇒dt = 1/sinxdx

⇒dt = cosecxdx

Putting it in the integration we get,

∫cosecx / log tan(x/2)dx

= ∫dt/t

= log∣t∣+c

= log∣logtan x/2∣+c where t = logtan x/2

7 0

3 years ago

Which equation demonstrates the additive identity property?

Bezzdna [24]

Answer:

Step-by-step explanation:

Solve for o in the equation (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 41o(7 + 4)(1) = 7 + 41o(7 + 41) + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 41o(7 + 4): Distribute the 41o to each term in (7+4)

41o * 7 = (41 * 7)o = 287o 41o * 4 = (41 * 4)o = 164o

Our Total expanded term is 287o + 164o

Simplify 41o(7 + 41): Distribute the 41o to each term in (7+41)

41o * 7 = (41 * 7)o = 287o 41o * 41 = (41 * 41)o = 1681o

Our Total expanded term is 287o + 1681o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o(1) = 7 + 287o + 1681o + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 164o(1): Distribute the 164o to each term in (1)

164o * 1 = (164 * 1)o = 164o Our Total expanded term is 164o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o = 7 + 287o + 1681o + ( - 7 - 41) = 0

Step 1: Group variables: We need to group our variables (7 and 14©(7. To do that, we subtract 14©(7 from both sides (7 - 14©(7 = 14©(7 - 14©(7

0o 0 = 0 0 o =

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3 years ago

Read 2 more answers

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Lina20 [59]

$\text {Percentage spent = } \dfrac{10}{25} \times 100$

$\text {Percentage spent = } \dfrac{2}{5} \times 100$

$\text {Percentage spent = } 40 \%$

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3 years ago

Read 2 more answers