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katovenus [111]
3 years ago
14

What is 25% of 160 show your work

Mathematics
1 answer:
givi [52]3 years ago
3 0

Answer:

40

Step-by-step explanation:

x / 160 = 25/100

x / 160 = 1/4

x = 1/4 * 160

x = 40

Hope this helps!

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7. Which pair shows equivalent expressions? A. 3(x+2) = 3x + 6 B. 3x + 2x = x²(x + 2) C. 3x + 2 = 3(x + 2) D. -3(2 + x) = -6x -
Sergio039 [100]
C has equivalent expressions I think
8 0
2 years ago
Solve for x or find x ​
ratelena [41]

the answer is x= 4

AB and CD are the same length

8x-1 =31

8x=32

x=4

4 0
3 years ago
A gram is equivalent to 0.0353 ounces. One ounce is how many grams? Round to the nearest tenth.
Artemon [7]

Answer:

Your answer is 28.3495

Brainliest is appreciated

5 0
2 years ago
Read 2 more answers
Write a quadratic function in vertex form whose graph has the vertex (-3,5) and passes through the point (0,-14)
dsp73

Answer:

f(x) = -19/9(x + 3)² + 5

Step-by-step explanation:

Given the vertex, (-3, 5) and the point, (0, 14):

Use the following quadratic equation formula in vertex form:

f(x) = a(x - h)² + k

where:

(h, k) = vertex

a = determines whether the graph opens up or down, and makes the graph wide or narrow.

<em>h</em><em> </em>= determines how far left or right the parent function is translated.

<em>k</em> =  determines how far up or down the parent function is translated.

Plug in the values of the vertex, (-3, 5) and the given point, (0, 14) to solve for <em>a</em>:

f(x) = a(x - h)² + k

14 = a(0 + 3)² + 5

14 = a(3)² + 5

14 = a(9) + 5

Subtract 5 from both sides:

-14 - 5 = 9a

-19 = 9a

Divide both sides by 9 to solve for a:

-19/9 = 9a/9

-19/9 = a

Therefore, the quadratic function in vertex form is:

f(x) = -19/9(x + 3)² + 5

Please mark my answers as the Brainliest, if you find this helpful :)

5 0
2 years ago
A pilot flew a 400 mile flight in 2.5 hours flying into the wind. Flying the same rate and with the same wind speed the return t
eduard

Answer: 20 mph

Explanation:

Speed is a physical quantity which is equal to the ratio between the distance covered (d) and the time taken (t):

v=\frac{d}{t}

In the first part of the problem, the plane flew a distance of d=400 mi in a time of t=2.5 h. The speed of the plane in this case was the difference between the proper speed of the plane, v, and the speed of the wind, w, since the plane flew opposite to the wind. So we can write:

v-w=\frac{400mi}{2.5h}=160 mph (1)

During the return trip, the plane flew with a speed (v+w), since the wind was on the tail, and it took 2 hours to cover the same distance:

v+w=\frac{400 mi}{2 h}=200 mph (2)

So we have two equations with two unknown variables. From (1), we get

v=160+w

Substituting into eq.(2)

(160+w)+w=200\\160+2w=200\\2w=40\\w=20 mph

So, the speed of the wind was 20 mph.

3 0
2 years ago
Read 2 more answers
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