Answer:
0.0714285metres, 0.07 metres
Step-by-step explanation:
100÷7 = 14.285...
5x14.285..=71.4285...
1/10 x 71.4285cm =7.142, 0.07metres
Answer:
Solutions are;
x = -8
x = -3.2
Step-by-step explanation:
Here, we want to solve the given equation for x
|(x-4)/(x + 5)| = 4
From what we have, this is an absolute value equation and thus, we are going to have two solutions
These are;
x-4/x+ 5 = 4
x-4 = 4(x + 5)
x-4 = 4x + 20
x-4x = 20 + 4
-3x = 24
x = -24/3
x = -8
secondly;
x-4/x+5 = -4
x-4 = -4(x + 5)
x-4 = -4x - 20
x + 4x = -20 + 4
5x = -16
x = -16/5
x = -3.2
Answer:
For the 2 the identical flower beds he will require 44 × 2 = 88 ft² of paints to paint the sides of the beds.
Step-by-step explanation:
The prisms are 2 identical flower beds . The dimensions are the same which have a length of 6 ft , height of 2 ft and width of 5 ft. He wants to paints the side of the beds which is the lateral area of the prisms.
Lateral surface area of a rectangular prism is adding the area of the lateral faces of the prism.
Lateral surface area = PH
P = perimeter of the side
H = height
perimeter = (2L + 2W)
where
L = length
W = width
L = 6 ft
W = 5 ft
perimeter = (2L + 2W)
perimeter = (2 × 6 + 2 × 5)
perimeter = (12 + 10)
perimeter = 22 ft
Lateral area = 22 × 2
Lateral area = 44 ft²
For the 2 the identical flower beds he will require 44 × 2 = 88 ft² of paints to paint the sides of the beds.
Answer:
B 5 seconds
Step-by-step explanation:
h = 240 + 32t – 16t^2
When is this equation 0
0 = 240 + 32t – 16t^2
Factor out 16
0 = -16(-15-2t+t^2)
= -16(t^2-2t-15)
What 2 numbers multiply to -15 and add to -2
-5*3 = -15
-5+3 =-2
0 = -16(t-5) (t+3)
Using the zero product property
t-5=0 t+3=0
t=5 t=-3
Since time cannot be negative
t=5 seconds
Answer:
Step-by-step explanation:
Given
i.e. first to fifth
Required
Determine number of selection
1st position = Any of the 30 students
2nd position = Any of the 29 students
3rd position = Any of the 28 students
4th position = Any of the 27 students
5th position = Any of the 26 students
Number of selection is then calculated as:
