All you have to do is isolate m. We have to move all terms except m to the other side.
15 + 5m = 415
We have to cancel out the numbers. 15 is being added so we subtract it from both sides.
15 - 15 + 5m = 415 - 15
5m = 400
5 is being multiplied so we divide it on both sides.
5m/5 = 400/5
m = 80
We can plug in to prove.
15 + 5(80) = 415
15 + 400 = 415
415 = 415
I think that the answer is 500 because i rounded it
Answer:
200
Step-by-step explanation:
we look at the tens place which is 8 since it greater than 5 we turn 8 and the number after into zeros and the 1 into a 2.
hope this welps :3
Answer:
height of the flag from the bottom of the boat ≈ 32 ft (nearest foot)
Step-by-step explanation:
She is on her boat and the angle of elevation to the top of the flag is 58°. Her eyes her 6 ft above the bottom of the boat she is sailing on. The height of the flag from the bottom of the boat is the sum of the height of the flag and the remaining height from the horizontal line of sight upward to the flag top.
A right angle triangle was formed Shianne line of sight. The angle from her line of sight is 58° from the horizontal. Therefore,
the adjacent side of the triangle formed is 16 ft which is the distance from the boat to the flag.
adjacent side = 16 ft
opposite angle = ?
using tangential ratio
tan 58° = opposite/adjacent
tan 58° = h/16
cross multiply
h = 16 × 1.60033452904
h = 25.6053524647
height of the flag from the bottom of the boat = 25.6053524647 + 6 = 31.6053524647
height of the flag from the bottom of the boat ≈ 32 ft(nearest foot)
One of the unknown angles (let's called it n) has a complement (meaning their sum adds up to 90 degrees) and the other angle is 8 times the unknown angle (8n)
With all this information, you should have the equation:
n + 8n = 90
To solve, combine like terms to get:
9n = 90
Divide by 9 on both sides to isolate the variable n.
n = 10
Now we plug back in to find our angle measurements. The first angle, n, is 10 degrees. The second angle, 8n, is 8 * 10 which is 80; the second angle is 80 degrees.
