Answer:
To prove that 3·4ⁿ + 51 is divisible by 3 and 9, we have;
3·4ⁿ is divisible by 3 and 51 is divisible by 3
Where we have;
= 3·4ⁿ + 51
= 3·4ⁿ⁺¹ + 51
- = 3·4ⁿ⁺¹ + 51 - (3·4ⁿ + 51) = 3·4ⁿ⁺¹ - 3·4ⁿ
- = 3( 4ⁿ⁺¹ - 4ⁿ) = 3×4ⁿ×(4 - 1) = 9×4ⁿ
∴ - is divisible by 9
Given that we have for S₀ = 3×4⁰ + 51 = 63 = 9×7
∴ S₀ is divisible by 9
Since - is divisible by 9, we have;
- 
= 
- is divisible by 9
Therefore is divisible by 9 and is divisible by 9 for all positive integers n
Step-by-step explanation:
Answer:
The answer is 19
Step-by-step explanation: 13 scored from 91-100, and 6 scored from 81-90, all you have to do is add them together.
Your answer will be D
As y = -(x+2)(x-1)
Thus the external negative sign will flip the positive 2 into a negative & negative 1 into a positive; Resulting, y=(x-2)(x+1)
Answer:
Linear systems are systems of equations in which the variables are never multiplied with each other but only with constants and then summed up
