Complementary angles --- they add up to 90 degrees
Answer:
3
Step-by-step explanation:
4(1/2+3/4)+(-2) Distribute.
2+3+(-2) Simplify.
2+3-2
5-2
3
Hope this helps!! Have an amazing day (｡･∀･)ﾉﾞ
Step-by-step explanation:
Statement:
2-) ∠BAC = ∠EDC
<em>Reason:</em>
Angles opposite to equal sides of a triangle are equal (Alternate Interior Angles Theorem)
Statement:
3-) AC = CD
<em>Reason:</em>
CPCTC ("Corresponding Parts of Congruent Triangles are Congruent")
Statement:
4-) ∠BCA = ∠DCE
<em>Reason:</em>
Vertical Angles Theorem (states that vertical angles, angles that are opposite each other and formed by two intersecting straight lines, are congruent)
Statement:
5-) triangle ABC = triangle DEC
ASA Postulate
The ASA (Angle-Side-Angle) postulate states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent. (The included side is the side between the vertices of the two angles.)
<h2>22</h2><h3>Answer: B</h3><h3 /><h2>23</h2><h3>Answer: D</h3><h3 /><h2>24</h2><h3>Answer: A</h3><h3 /><h2>25</h2><h3>Answer: C</h3>
Answer:
Step-by-step explanation:
To prove Δ ABC similar to ΔDBE we can consider
Segments AC and DE are parallel.
⇒ DE intersects AB and BC in same ratio.
AB is a transversal line passing AC and DE.
⇒∠BAC=∠BDE [corresponding angles]
Angle B is congruent to itself due to the reflexive property.
All of them are telling a relation of parts of ΔABC to ΔDBE.
The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".
Answer: -14v-24
Step-by-step explanation:
2v-8(3+2v)
2v-(24+16v)
2v-24-16v
-14v-24
