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3 years ago

Blue paper chains 4 inches long. Red paper chains are 3 inches long. How many are needed to have 10 inches of paper chains?

Mathematics

2 answers:

bixtya [17]3 years ago

7 0

1 blue paper chain and 2 red paper chains

Alenkasestr [34]3 years ago

3 0

Answer:

1 blue paper chains and 2 red

Step-by-step explanation:

becuase 4 plus 3 plus 3 is 10

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PLZ IM BEGGING YOU

antoniya [11.8K]

Answer:

200

Step-by-step explanation:

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2 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago

I need help with question 2c

Step2247 [10]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the volume in cubic units of a cylinder diameter 6 and height 4

katrin2010 [14]

Hey there!

The formula for the volume of a cylinder is $\pi r^{2} h$ , which is essentially the base multiplied by the height.

If our diameter is six, then our radius is three, so we can solve for our base below. We will use 3.14 for pi.

$3^{2}(3.14)=28.26$

Now, we multiply this by our height of four.

$28.26(4)=113.04$

Therefore, our volume is 113.04 cubic units.

I hope this helps!

3 0

3 years ago

Danny made a mistake in the following problem.

Olenka [21]

The mistake is made on line 3, after calculating 35/7, he should have started with the multiplication 6(2)

7 0

3 years ago