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3 years ago

Can anyone help with this please

Mathematics

1 answer:

marshall27 [118]3 years ago

4 0

Answer:the correct answer is b

Step-by-step explanation:

Took the test also download the app called photo math all I have to do is take the photo of the problem it’s free of charge

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Jill wrote the number 40. if her rule is add 7 what is the fourth number in jills pattern

Sedbober [7]

1) 40+7=47
2) 47+7= 54
3) 54+7 = 61
4) 61+7 = 68
The answer is 68.

6 0

3 years ago

You have a 5-question multiple-choice test. Each question has four choices. You don’t know any of the answers. What is the exper

lana66690 [7]

2 out of 5 chance that you will attests get 3

4 0

3 years ago

Ryan is remodeling his kitchen floor, which is 110 square feet. He used

irakobra [83]

Answer:

He will need 9 tiles

Step-by-step explanation:

Step one:

let us highlight the given parameters

Given data

the size of the kitchen floor is 110 ft^2

the size of the bathroom is 28 ft^2

he used 32.5 tiles for the kitchen

and used x tiles for the bathroom

Step two:

if he used 32 tiles for 110 ft^2 kitchen

he will use x tiles for 28 ft^2 bathroom

cross multiplying we have

x= (32*28)/110

x= 896/110

x= 8.145

Approximately he will need 9 tiles

4 0

3 years ago

A researcher selects two samples of equal size and computes a mean difference of 1.0 between the two sample means. If the pooled

s344n2d4d5 [400]

Answer:

The Cohen's D is given by this formula:

$D = \frac{\bar X_A -\bar X_B}{s_p}$

Where $s_p$ represent the deviation pooled and we know from the problem that:

$s^2_p = 4$ represent the pooled variance

So then the pooled deviation would be:

$s_p = \sqrt{4}= 2$

And the difference of the two samples is $\bar X_a -\bar X_b = 1$ , and replacing we got:

$D = \frac{1}{2}= 0.5$

And since the value for D obtained is 0.5 we can consider this as a medium effect.

Step-by-step explanation:

Previous concepts

Cohen’s D is a an statistical measure in order to analyze effect size for a given condition compared to other. For example can be used if we can check if one method A has a better effect than another method B in a specific situation.

Solution to the problem

The Cohen's D is given by this formula:

$D = \frac{\bar X_A -\bar X_B}{s_p}$

Where $s_p$ represent the deviation pooled and we know from the problem that:

$s^2_p = 4$ represent the pooled variance

So then the pooled deviation would be:

$s_p = \sqrt{4}= 2$

And the difference of the two samples is $\bar X_a -\bar X_b = 1$ , and replacing we got:

$D = \frac{1}{2}= 0.5$

And since the value for D obtained is 0.5 we can consider this as a medium effect.

7 0

3 years ago

The top and bottom margins of a poster 66 cm each, and the side margins are 44 cm each. If the area of the printed material on t

jasenka [17]

Answer:

width: 24 cm
height: 36 cm

Step-by-step explanation:

When margins are involved, the smallest area will be the one that has its dimensions in the same proportion as the margins. If x is the "multiplier", the dimensions of the printed area are ...

(4x)(6x) = 384 cm^2

x^2 = 16 cm^2 . . . . . divide by 24

x = 4 cm

The printed area is 4x by 6x, so is 16 cm by 24 cm. With the margins added, the smallest poster will be ...

24 cm by 36 cm

_____

Comment on margins

It should be obvious that if both side margins are 4 cm, then the width of the poster is 8 cm more than the printed width. Similarly, the 6 cm top and bottom margins make the height of the poster 12 cm more than the height of the printed area.

_____

Alternate solution

Let w represent the width of the printed area. Then the printed height is 384/w, and the total poster area is ...

A = (w+8)(384/w +12) = 384 +12w +3072/w +96

Differentiating with respect to w gives ...

A' = 12 -3072/w^2

Setting this to zero and solving for w gives ...

w = √(3072/12) = 16 . . . . matches above solution.

Generic solution

If we let s and t represent the side and top margins, and we use "a" for the printed area, then the above equation becomes the symbolic equation ...

A = (w +s)(a/w +t)

A' = t - sa/w^2

For A' = 0, ...

w = √(sa/t)

and the height is ...

a/w = a/√(sa/t) = √(ta/s)

Then the ratio of width to height is ...

w/(a/w) = w^2/a = (sa/t)/a

width/height = s/t . . . . . . the premise we started with, above

6 0

3 years ago