This is the question in full: Jeff is making fruit punch for the school dance. He needs 3 3/4 cups of pineapple juice per batch.
If Jeff wants to make
4 1/2 batches of punch, how many cups of pineapple juice will he need?
4 1/2 batches of punch, how many cups of pineapple juice will he need?
1 answer:
You might be interested in
Answer:
a) 0.5488 = 54.88% probability that the family did not make a trip to an amusement park last year.
b) 0.3293 = 32.93% probability that the family took exactly one trip to an amusement park last year.
c) 0.1219 = 12.19% probability that the family took two or more trips to amusement parks last year.
d) 0.8913 = 89.13% probability that the family took three or fewer trips to amusement parks over a three-year period.
e) 0.1912 = 19.12% probability that the family took exactly four trips to amusement parks during a six-year period.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Poisson distributed, with a mean of 0.6 trips per year
This means that , in which n is the number of years.
a.The family did not make a trip to an amusement park last year.
This is P(X = 0) when n = 1, so .
0.5488 = 54.88% probability that the family did not make a trip to an amusement park last year.
b.The family took exactly one trip to an amusement park last year.
This is P(X = 1) when n = 1, so .
0.3293 = 32.93% probability that the family took exactly one trip to an amusement park last year.
c.The family took two or more trips to amusement parks last year.
Either the family took less than two trips, or it took two or more trips. So
We want
In which
0.1219 = 12.19% probability that the family took two or more trips to amusement parks last year.
d.The family took three or fewer trips to amusement parks over a three-year period.
Three years, so .
This is
0.8913 = 89.13% probability that the family took three or fewer trips to amusement parks over a three-year period.
e.The family took exactly four trips to amusement parks during a six-year period.
Six years, so .
This is P(X = 4). So
0.1912 = 19.12% probability that the family took exactly four trips to amusement parks during a six-year period.
Answer:
1) Function; Linear Function (y=x)
2) Function; Exponential Function (y=bˣ)
3) Not a function.
Step-by-step explanation:
So, let's go through each table of values. I'm also going to graph them (see attached graphs) because it will make things simpler and provide a visual.
First, also recall what the definition of a function is. A function is a function if and only if an x only has <em>one</em> distinct y-value. No x can have two or more y-values. For instance, (1,2) and (1,3) is <em>not</em> a function between the x repeats. So, let's go through the choices:
1)
We have the table as shown. Let's plot the points. See TABLE 1:
First, there are no repeating x-values, so we can be sure that this is indeed a function.
Looking at the graph, we can see that this resembles a linear graph. So, the parent function of this is a line.
The parent function of a line is:
So, table 1 is associated with a linear function.
2)
Let's again plot the points. See TABLE 2.
Again, there are no repeating x-values, so this is also a function.
Looking at the graph, this resembles an exponential function. The function increases slowly at first but starts increasing increasingly fast. The parent function is thus an exponential function.
So, table 2 is associated with an exponential function.
3)
First, notice how all the x-coordinates are repeating. And since they do <em>not</em> equal the same thing, this is not a function.
Table 3 is not a function and so has no corresponding family function.
