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galina1969 [7]
3 years ago
12

Please take a look at the picture.

Mathematics
1 answer:
Lisa [10]3 years ago
6 0

Answer:

I think it is total cost

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1.
RUDIKE [14]

Answer:

Answer:

For converging lens

object distance u = - 2.0cm

Focal length f = 5.0cm

From lens formula

m=

m=

=3

Size of image = size of object x Magnification

= 2 x .10 = 2.0cm

For diverging lens

object distance u = 140 - 120 = 20 cm

focal length f = -30 cm

frac{1}{v}+\frac{1}{20}=-\frac{1}{30}

v = -12 cm

m = 12/20 = 0.6

size of final image = .6 x 30 = 18 cm

3 0
4 years ago
Find the quotient: 3 3/4 ÷ 2
Westkost [7]

Answer:

1\frac{7}{8}

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A new park was designed to contain two circular gardens. Garden A has a diameter of 50 m, and garden B has a diameter of 70 m. T
Nastasia [14]

Answer:

5,811.95\  m^2 of fabric.

Step-by-step explanation:

-The amount of fabric needed is equivalent to the  area of the two gardens.

-We calculate the combined areas as:

A=A_s+A_b\\\\=\pi r^2+\pi R^2\\\\=\pi(25^2+35^2)\\\\=1850\pi \ m^2\\\\=5811.95\ m^2

Hence, 5811.95 sq meters of fabric will be needed to cover the area of both gardens.

5 0
4 years ago
Find the slope of the line that's passing through (2,2) and (-1, -2)
irga5000 [103]
Slope=(y2-y1)/(x2-x1)
=((-2-)2)/((-1)-2)
= (-4) / (-3)
= 4/3

the answer is A

hope I can help u
5 0
3 years ago
Read 2 more answers
1)Find the third side of a triangle when two sides of the triangle is 4 and the included angle measuring 89 degrees
Sergio039 [100]

Answer:

1) The length of the third side is 5.607 units

2) The sum of the numbers from 1 to 100 is 5050

3) For the x-axis, foci: ((√15/28), 0) and (-(√15/28), 0)

For the y-axis, foci: (0, (√15/28)) and (0, -(√15/28))

Step-by-step explanation:

1) When two sides of the triangle are equal to 4 then the triangle is an isosceles triangle

Given that the included angle (the angle between the two sides) is 89°, we have;

The other two base angles are equal to {180 - 89)/2 = 91/2 = 45.5°

Therefore, we have from cosine rule;

a² = b² + c² - 2·b·c·cos(A)

We note that the angle opposite the third side is the included angle 89°, therefore, when we put a as the third side in the above equation, we have;

a² = 4² + 4² - 2×4×4×cos(89°)

a² = 31.44

a = 5.607

The length of the third side is 5.607 units

2) The numbers 1 to 100 form an arithmetic series with the first term, a = 1 and the common difference, d = 1 with the number of terms n = 100

The sum of an arithmetic progression, Sₙ, is given as follows;

S_n = \dfrac{n}{2}\cdot (2 \cdot a + (n - 1) d)

Therefore, by plugging in the values, we have;

Sₙ = 100/2*(2*1 + (100 - 1)*1) = 100/2*(101) = 5050

The sum of the numbers from 1 to 100 is 5050

3) The foci of an ellipse 7·x² + 8·y² = 30 is found as follows;

Dividing both sides of the equation by 30 gives;

7/30·x² + 8/30·y² = 30/30

7/30·x² + 8/30·y² = 30/30

7/30·x² + 4/15·y² = 1

Which is of the form;

x²/a² + y²/b² = 1

For the x-axis we have

c² = a² - b²

c² = 30/7 - 15/4 = 15/28

h = 0, k = 0

Foci: ((√15/28), 0) and (-(√15/28), 0)

For the y-axis, we have;

x²/b² + y²/a² = 1

The foci are then (0, (√15/28)) and (0, -(√15/28)).

6 0
4 years ago
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