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djverab [1.8K]
3 years ago
7

Really need an answer to this please help.

Mathematics
1 answer:
Alex3 years ago
7 0

Answer:

a

Step-by-step explanation:

\sqrt[4]{144a^{12}b^{3}} = \sqrt[4]{4^{2}*3^{2}a^{12}b^{3}}=\\= \sqrt[4]{2^{4}*3^{2}a^{12}b^{3}}=2a^{3}\sqrt[4]{3^{2}b^{3}} =\\}=2a^{3}\sqrt[4]{9b^{3}}

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If a is the average (arithmetic mean) of 4x and 7, b is the average of 5x and 6, and c is the average of 3x and 11, what is the
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Answer:

2x+4

Step-by-step explanation:

Given that a is the average (arithmetic mean) of 4x and 7, b is the average of 5x and 6, and c is the average of 3x and 11

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Read 2 more answers
8 3/8 = r- 2 1/3 how do i solve this equation by finding out what r is.
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3 years ago
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