Answer:
The fraction of the offspring that will show the phenotype produced by the recessive c allele is 1024/4096 = 0.25 A-BbccDdE-Ff = 25%
Explanation:
You can calculate the fraction of the offspring that will show the phenotype produced by the recessive c allele by making the punnet square for each gene and then multipling the phenotypic proportions, like this:
Cross) AAbbCcDDEeff x AaBBCcddEEFF
Cross For each gene by separately:
Gametes) A A A a
F1) 2/4 AA
2/4 Aa
Gametes) b b B b
F1) 4/4 Bb
Gametes) C c C c
F1) 1/4 CC
2/4 Cc
1/4 cc
Gametes) D D d d
F1) 4/4 Dd
Gametes) E e E E
F1) 2/4 Ee
2/4 EE
Gametes) f f F F
F1) 4/4 Ff
So, fraction of the offspring that will show the phenotype produced by the recessive c allele is:
4/4 A- x 4/4 Bb x 1/4 cc x 4/4 Dd x 4/4 E- x 4/4 Ff =
1024/4096 = 0.25 A-BbccDdE-Ff =25%
<span>Dr. Stott is researching epigenetics. Epigenetics is the study of changes that occur in gene expression with no changes in the actual gene sequences. Environmental factors can influence gene expression without changing the DNA sequence, making this the study of epigenetics.</span>
I'm thinking either the first or second answer. Sorry if this doesn't help.<span />
The doctor is recommending the intake of a serotonin agonist that will activate the <span>5-HT receptors. There are several agonists for these receptors being </span>Lorcaserin one of the most used ones in <span>weight-loss</span>, which is a selective agonist for
receptors.
