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STALIN [3.7K]
3 years ago
11

Which equation is equivalent to the given equation? 7m + 11 = -4 (2m +3)

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer:

15m=-23

Step-by-step explanation:

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I don’t understand this problem
Wittaler [7]

68x87 i think?

sorry if that isnt right..

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3 years ago
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-0.3x(12x2-0.3x+0.5)
slava [35]
The answer is -7.35x+0.09x to the power of 2
8 0
3 years ago
The length of ZX is 2 units. What is the perimeter of triangle XYZ?
dezoksy [38]

Keywords

triangle,perimeter,distance, length, side, points

we know that

The <u>perimeter</u> of a<u> triangle</u> is the sum of the three <u>length</u> <u>side</u>

To find the<u> length</u> <u>side</u> calculate the <u>distance</u> between two <u>points</u>

The formula to calculate the <u>distance</u> between to <u>points</u> is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}


Step 1

Find the <u>distance</u> ZY

Z(1,0)\\Y(3,1)  

substitute the values


d=\sqrt{(1-0)^{2}+(3-1)^{2}}


dZY=\sqrt{5}\ units


Step 2

Find the <u>distance</u> XY

X(-1,4)\\Y(3,1)  

substitute the values


d=\sqrt{(1-4)^{2}+(3+1)^{2}}


dXY=\sqrt{25}=5\ units  

Step 3

Find the <u>perimeter</u> of the <u>triangle</u>

P=ZX+ZY+XY

we have

dZX=2\sqrt{5}\ units


dZY=\sqrt{5}\ units


dXY=5\ units  

Substitute

P=(2\sqrt{5}+\sqrt{5}+5)\ units

therefore

the answer is

P=(3\sqrt{5}+5)\ units

4 0
3 years ago
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Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and
tia_tia [17]

p=501\cdot503\cdot\cdots\cdot597

q=\underbrace{501\cdot503\cdot\cdots\cdot597}_p\cdot599\cdot601

So we have q=359,999p. Then

\dfrac1p+\dfrac1q=\dfrac{359,999}{359,999p}+\dfrac1q=\dfrac{359,999+1}q=\dfrac{360,000}q

and the answer is D.

4 0
3 years ago
$800 is deposited in an account
Sergeeva-Olga [200]

Answer:

The balance after four years is $1129.27

Step-by-step explanation:

The formula for compound interest, including principal sum, is A=P(1+\frac{r}{n})^{nt}

  • A = the future value of the investment/loan, including interest
  • P = the principal investment amount (the initial deposit or loan amount)
  • r = the annual interest rate (decimal)
  • n = the number of times that interest is compounded per unit t
  • t = the time the money is invested or borrowed for

∵ $800 is deposited in an account

∴ P = 800

∵ The account pays 9% annual interest

∴ r = 9% = 9 ÷ 100 = 0.09

∵ The interest is compounded annually

∴ n = 1

∵ The time is 4 years

∴ t = 4

- Substitute the values of P, r, n, and t in the formula above

∵ A=800(1+\frac{0.09}{1})^{(1)(4)}

∴ A=800(1.09)^{4}

∴ A = 1129.265

∴ The balance after four years is $1129.27

8 0
3 years ago
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