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Yuliya22 [10]
2 years ago
10

A box of cereal states that there are 81 calories in a 7-cup serving. What is the unit rate for calories

Mathematics
1 answer:
mr_godi [17]2 years ago
5 0

Answer:

23.142857143 calories or 23 1/7 calories

The unit rate is calories per cup

Step-by-step explanation:

7- cup serving = 81 calories

2 cups = x calories

Cross Multiply

2 cups × 81 calories = 7 cups × x

x = 2 cups × 81 calories/7 cups

x = 23.142857143 calories or 23 1/7 calories

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Ieda and Thanh both offer piano lessons. Ieda charges an initial fee of $8.50 and an hourly rate of $11.00. Thanh charges an ini
Trava [24]
The price for each instructor will be the same at 3 hours. How I determined this answer:

First off, you need to add the initial price and hourly price for each person together, so you already know how much it will cost for 1 hour, including the initial fee. Here's how you do it:

Ieda: $11.00 (hourly price) + $8.50 (initial fee) = $19.50 (for 1 hour)

Thanh: $10.50 (hourly price) + $10.00 (initial fee) = $20.50 (for 1 hour)

Now that you have the price for 1 hour including the initial fee, now you need to find the price for each hour after that. Here's how I did that:

I created a graph that looked like this:

Hours:       1                 2                  3               
Ieda:      19.50          30.50         41.50
Thanh:   20.50          31.00         41.50

Here's how I figured out the price for each hour:

Ieda:

Hour 1 (including initial price):
            $11.00 + $8.50 = $19.50
Hour 2 (excluding initial price): Only add the hourly price after Hour 1!
            $19.50 + $11.00 = $30.50 
Hour 3 (excluding initial price):
            $30.50 + $11.00 = $41.50

Thanh:

Hour 1 (including initial price):
            $10.50 + $10.00 = $20.50
Hour 2 (excluding initial price):
            $20.50 + $10.50 = $31.00
Hour 3 (excluding initial price):
            $31.00 + $10.50 = $41.50

So, looking at the graph, their prices are the same once each instruction reaches 3 hours. ($41.50)

I hope I was able to help you! :)
5 0
2 years ago
Read 2 more answers
The sum of four consecutive integers is 166. Find the largest of the numbers if the smallest is z.
hjlf
4 consecutive integers...z, z + 1, z + 2, z + 3

z + (z + 1) + (z + 2) + (z + 3) = 166...combine like terms
4z + 6 = 166
4z = 166 - 6
4z = 160
z = 160/4
z = 40

z + 1 = 40 + 1 = 41
z + 2 = 40 + 2 = 42
z + 3 = 40 + 3 = 43

so ur numbers are : 40,41,42,43 with the largest being 43
8 0
3 years ago
Which list correctly orders A, B, and C from least to greatest when A = –8, B = StartAbsoluteValue negative 6 EndAbsoluteValue,
vladimir2022 [97]

Answer:

A, B, C

Step-by-step explanation:

A = -8

B = |-6| = 6

C = |11| = 11

Least to greatest, negatives are the least and between 6 and 11, 11 is the greatest.

3 0
2 years ago
Read 2 more answers
Joni has a circular garden with a diameter of 14 1/2 feet if she uses 2 teaspoons of fertilizer for every 25 square feet of gard
alina1380 [7]

Answer:

13.20 teaspoon of fertiliser needed for entire garden.

Step-by-step explanation:

Diameter of the garden = 14.50 ft

Radius of the garden = 7.25 ft

Area

[tex]A=\pi r^2[/text]

[tex]A=\pi \times 7.25 \times 7.25[/text]

[tex]\pi=3.14[/text]

[tex]A=\pi \times 7.25 \times 7.25[/text]

[tex]A=3.14 \times 7.25 \times 7.25[/text]

Hence

[tex]A=165.046[/text]

Area is 165.046 Sq Ft

For 25 sq ft of fields the fertiliser needed = 2 tea spoon

For 1 sq ft of fields the fertiliser needed =

[tex]\frac{2}{25}[/text] tea spoon

For 165.046 sq ft of fields the fertiliser needed =

[tex]\frac{2 \times 165.046 }{25}[/text] tea spoon

For 165.046 sq ft of fields the fertiliser needed = 13.20 tea spoon

6 0
3 years ago
The annual energy consumption of the town where Camilla lives in creases at a rate that is onal at any time to the energy consum
boyakko [2]

Answer:

6.575 trillion BTUs

Step-by-step explanation:

<em>Let represent the annual energy consumption of the town as E</em>

<em>The rate of annual energy consumption *  energy consumption at time past</em>

<em>dE/dt * E</em>

<em>dE/dt =K</em>

<em>k = the proportionality constant</em>

<em>c= the integration constant</em>

<em>(dE/dt=) kdt</em>

<em>lnE = kt + c</em>

<em>E(t) = e^kt+c ⇒ e^c e^kt  e^c is a constant, and e^c = E₀</em>

<em>E(t) = E₀ e^kt</em>

<em>The initial consumption of energy is E(0)=4.4TBTU</em>

<em>set t = 0 then</em>

<em>4.4 = E₀ e⇒ E₀ (1) </em>

<em>E₀ = 4.4</em>

<em>E (t) = 4.4e^kt</em>

<em>The consumption after 5 years is t = 5, e(5) = 5.5TBTU</em>

<em>so,</em>

<em>E(5) = 5.5 = 4.4e^k(5)</em>

<em>e^5k = 5/4</em>

<em>We now take the log 5kln = ln(5/4)</em>

<em>5k(1) = ln(5/4)</em>

<em>k = 1/5 ln(5/4) = 0.04463</em>

<em>We find  the town's annual energy consumption, after 9 years</em>

<em>we set t=9  </em>

<em>E(9) = 4.4e^0.04463(9)</em>

<em>= 4.4(1.494301) = 6.5749TBTUs</em>

<em>Therefore the annual energy consumption of the town after 9 years is </em>

<em>= 6.575 trillion BTUs</em>

<em />

3 0
3 years ago
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