Answer:
C. ± 2.326 years.
Step-by-step explanation:
We have the standard deviation for the sample. So we use the t-distribution to solve this question.
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so ![z = 2.326/tex]Now, find the width of the interval[tex]W = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=z%20%3D%202.326%2Ftex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3ENow%3C%2Fstrong%3E%2C%20find%20the%20width%20of%20the%20interval%3C%2Fp%3E%3Cp%3E%5Btex%5DW%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which 
is the standard deviation of the population and n is the size of the sample.
In this question:
So
The correct answer is:
C. ± 2.326 years.
Answer:
1 solution and that is that x = -1
Step-by-step explanation:
First Step: Leave "x" alone, pass the 3 to the other side
X= 10+3
Second Step: Add 10 plus 3
X= 13
So your answer is: x=13
Product means the answer/result to a multiplication problem
Estimate means to form an approximation/ rough guess
126.12 x 2.2 = 277.464
This answer, 277.464, is the exact product
Its wanting us to find the estimate (there could be possible estimates, depending on what the instructions is asking for):
- 277
- 280
- 300
