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3 years ago

5+ 1/5x=5 what is x

Mathematics

2 answers:

Alenkasestr [34]3 years ago

4 0

Answer:

x = 0

Step-by-step explanation:

Solve for x:

x/5 + 5 = 5

Put each term in x/5 + 5 over the common denominator 5: x/5 + 5 = x/5 + 25/5:

x/5 + 25/5 = 5

x/5 + 25/5 = (x + 25)/5:

(x + 25)/5 = 5

Multiply both sides of (x + 25)/5 = 5 by 5:

(5 (x + 25))/5 = 5×5

(5 (x + 25))/5 = 5/5×(x + 25) = x + 25:

x + 25 = 5×5

5×5 = 25:

x + 25 = 25

Subtract 25 from both sides:

x + (25 - 25) = 25 - 25

25 - 25 = 0:

x = 25 - 25

25 - 25 = 0:

Answer: x = 0

Kisachek [45]3 years ago

4 0

Answer: (distributive property)

20.

1/5 + 1/5 + 1/5 + 1/5 + 1/5 = 5/5 or 1

= 5 (total sums)

The total number of 1/5's = 25

20 + 5 = 25

25 - 5 = 20

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3 years ago

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Step-by-step explanation:

Formula to find the sample size :

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Given : Confidence level : $(1-\alpha)=0.90$

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8 0

4 years ago

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Find the missing side lengths. Leave your answer as radicals in simplest form.

inn [45]

Answer:

Solution given:

b=9 base side of isosceles triangle

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3 years ago

HEEELP

Drupady [299]

Answer: (c)

Step-by-step explanation:

Given

$f(x)=\dfrac{1}{x-3}\\\\g(x)=\sqrt{x+5}$

Here, $\sqrt{x+5}\ \text{is always greater than equal to 0}\\\Rightarrow x+5\geq 0\\\Rightarrow x\geq -5\quad \ldots(i)$

To get $f\left(g(x)\right)$ , replace $x$ in $f(x)$ by $g(x)\ \text{i.e. by}\ \sqrt{x+5}$

$\Rightarrow f\left(g(x)\right)=\dfrac{1}{\sqrt{x+5}-3}\\\\\text{Denominator must not be equal to 0}\\\\\therefore \sqrt{x+5}-3\neq0\\\Rightarrow \sqrt{x+5}\neq 3\\\Rightarrow x+5\neq 9\\\Rightarrow x\neq 4\quad \ldots(ii)$

Using $(i)$ and $(ii)$ it can be concluded that the domain of $f\left(g(x)\right)$ is all real numbers except 0.

Therefore, its domain is given by

$x\in [-5,4)\cup (4,\infty)$

Option (c) is correct.

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3 years ago

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Crazy boy [7]

18.5-0.5= 18 18/3= 6 So r=6

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3 years ago

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