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3 years ago

What is radian measure in geometry? what do you use it for?

Mathematics

2 answers:

trapecia [35]3 years ago

8 0

Answer:

The radian is a unit of measure for angles used mainly in trigonometry. It is used instead of degrees. ... As seen in the figure above, a radian is defined by an arc of a circle. The length of the arc is equal to the radius of the circle. Because of this the radian is a fixed size no matter what the size of the circle is.

Step-by-step explanation:

Strike441 [17]3 years ago

8 0

Answer:

The radian is a unit of measure for angles used mainly in trigonometry. It is used instead of degrees.

Step-by-step explanation:

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Match each value with its formula for ABC.

MariettaO [177]

The solution to the question is:

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

<h3>What is cosine rule?</h3>

it is used to relate the three sides of a triangle with the angle facing one of its sides.

The square of the side facing the included angle is equal to the some of the squares of the other sides and the product of twice the other two sides and the cosine of the included angle.

Analysis:

If c is the side facing the included angle C, then

$c^{2}$ = $a^{2}$ + $b^{2}$ -2ab cos C-----------------1

then c = $\sqrt{a^{2} + b^{2} -2abcosC }$

if b is the side facing the included angle B, then

$b^{2}$ = $a^{2}$ + $c^{2}$ -2accosB-----------------2

b = $\sqrt{a^{2} + c^{2} -2accosB }$

from equation 2, make cosB the subject of equation

2ac cosB = $a^{2}$ + $c^{2}$ - $b^{2}$

cosB = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

if a is the side facing the included angle A, then

$a^{2}$ = $b^{2}$ + $c^{2}$ -2bccosA--------------------3

a = $\sqrt{b^{2} + c^{2} -2bccosA }$

from equation 3, making cosA subject of the equation

2bcosA = $b^{2}$ + $c^{2}$ - $a^{2}$

cosA = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

from equation 1, making cos C the subject

2abcosC = $b^{2}$ + $a^{2}$ - $c^{2}$

cos C = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

In conclusion,

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

Learn more about cosine rule: brainly.com/question/4372174

$SPJ1

4 0

2 years ago

Question 1 (Multiple Choice Worth 5 points)

katrin [286]

Uurcrcucrvurctuccecuwxrve

5 0

3 years ago

A large food-processing plant requires 1.5 lbm/s of saturated or slightly superheated steam at 140 psia, which is extracted from

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3 years ago

Could someone help me answer this? <br> Solve -2log8(x + 1) = -8.<br> Thanks so much!

drek231 [11]

Step one, divide both sides by -2
log8(x+1)=4

if the base is 10, and the 8 is together with (x+1): (cannot tell from the way it is written)
8(x+1)=10^4=10000
x+1=1250
x=1249

if the 8 is a base,
8^4=(x+1)
x+1=4096
x=4095

8 0

3 years ago

I need the answer asap2.794 x 10^9

faltersainse [42]

Answer:

2794000000

Step-by-step explanation:

2.794 x 10^9

= 2794000000

8 0

3 years ago

What is radian measure in geometry? what do you use it for?​

What is radian measure in geometry? what do you use it for?