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nirvana33 [79]
3 years ago
15

Lisa is writing a coordinate proof to show that the diagonals of a square are perpendicular to each other. she starts by assigni

ng coordinates as given. a square is graphed on a coordinate plane. the horizontal x-axis and y-axis is solid and grid is hidden. the vertices are labeled as k, g, h and j. the vertex labeled as k lies on begin ordered pair 0 comma 0 end ordered pair. the vertex labeled as g lies on begin ordered pair 0 comma a end ordered pair. the vertex labeled as j lies on begin ordered pair a comma 0 end ordered pair. one vertex is unlabeled. diagonal k h and g j are drawn. drag and drop the correct answers to complete the proof. since ghjk is a square, the coordinates of h are (a, ). the slope of kh¯¯¯¯¯¯ is . the slope of is −1 . the product of the slopes of the diagonals is . therefore, kh¯¯¯¯¯¯ is perpendicular to gj¯¯¯¯¯ . 10−1agj¯¯¯¯¯gk¯¯¯¯¯¯

Mathematics
2 answers:
gavmur [86]3 years ago
6 0

Answer:

Just took the test and got the correct answer. :)))

Step-by-step explanation:

Look at the image down below!

kondaur [170]3 years ago
4 0
Your a cheater, k12 will expel cheaters..... jk lol but the answers are

Since GHJK is a square, the coordinates of H are (a, a).
The slope of KH¯¯¯¯¯¯ is 1.
The slope of GJ¯¯¯¯¯ is −1 .
The product of the slopes of the diagonals is −1.
The product of the slopes of the diagonals is −1.

Good luck, and really study, because the finals test will be difficult, and use the geometry reference guide.... It covers the fundamentals
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PLEASE HELP ME I AM ON A TEST
Juliette [100K]

The equation in slope-intercept form represents a line that is parallel to y = 12x − 2 and passes through the point (−8,1) is y = 12x + 97

<em><u>Solution:</u></em>

Given that we have to write the equation in slope intercept form for line that is parallel to y = 12x − 2 and passes through the point (−8, 1)

<em><u>The slope intercept form is given as:</u></em>

y = mx + c  ---- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given equation of line is y = 12x - 2

On comparing the above equation with eqn 1,

m = 12

Thus slope of line is 12

We know that slopes of parallel lines are equal

Therefore, slope of line parallel to given line is also 12

Given point is (-8, 1)

We have to find the equation of line passing through (-8, 1) with slope m = 12

Substitute m = 12 and (x, y) = (-8, 1) in eqn 1

1 = 12(-8) + c

1 = -96 + c

c = 97

Substitute c = 97 and m = 12 in eqn 1

y = 12x + 97

Thus the required equation of line is found

6 0
2 years ago
Karl is thinking of holding a mini lottery to raise money.
Katena32 [7]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Write an exponential function y = ab" whose graph passes through (2,12) and (5,96).
motikmotik

Answer:

y = 3(2)^{x}

Step-by-step explanation:

Substitute the given points into the function and solve for a and b

Using (2, 12)

12 = ab² → (1)

Using (5, 96)

96 = ab^{5} → (2)

Divide (2) by (1)

\frac{ab^5}{ab^2} = \frac{96}{12} , that is

b³ = 8 ( take the cube root of both sides )

b = \sqrt[3]{8} = 2

Substitute b = 2 into (1) and solve for a

12 = a2² = 4a ( divide both sides by 4 )

3 = a

Thus

y = 3(2)^{x} ← is the exponential function

3 0
3 years ago
Which equation is represented by the graph below?
Levart [38]
The correct answer is the first choice
3 0
3 years ago
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Alexus [3.1K]

Answer:

For #3 the answer is 113.04 (6 + g) / 32

Step-by-step explanation:

A = Pi * r * (r + g)

12/2 = 6 ft

A = 3.14 * (6) * (6 + g) = 113.04 (6 + g) square feet

113.04 (6 + g) / 32

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