Lisa is writing a coordinate proof to show that the diagonals of a square are perpendicular to each other. she starts by assigni
ng coordinates as given. a square is graphed on a coordinate plane. the horizontal x-axis and y-axis is solid and grid is hidden. the vertices are labeled as k, g, h and j. the vertex labeled as k lies on begin ordered pair 0 comma 0 end ordered pair. the vertex labeled as g lies on begin ordered pair 0 comma a end ordered pair. the vertex labeled as j lies on begin ordered pair a comma 0 end ordered pair. one vertex is unlabeled. diagonal k h and g j are drawn. drag and drop the correct answers to complete the proof. since ghjk is a square, the coordinates of h are (a, ). the slope of kh¯¯¯¯¯¯ is . the slope of is −1 . the product of the slopes of the diagonals is . therefore, kh¯¯¯¯¯¯ is perpendicular to gj¯¯¯¯¯ . 10−1agj¯¯¯¯¯gk¯¯¯¯¯¯
2 answers:
You might be interested in
Answer:
n = 6 + or n = 6 -
Step-by-step explanation:
We can solve this equation using the quadratic formula OR Completing the Square method.
n² + 14 = 12n
rearrange : n² - 12n + 14 = 0
here a= 1 , b = -12, c = 14
the quadratic formula says: x = - b/ (2a) + root(b^2 - 4ac) / (2a)
or x = - b/ (2a) - root(b^2 - 4ac) / (2a)
x = - (-12)/ (2) + root((-12)^2 - 4*14) / (2)
x = 6 + root (144 - 56) / 2
x = 6 + root(88)/2
x = 6 + root(4*22) / 2
x = 6 + 2*root(22)/2
x = 6 + root(22) = 6 +
so x =6 + or x = 6 -
In this case x = n
n = 6 + or n = 6 -
