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ozzi
3 years ago
6

Is ΔFGH~ΔJKL? If so, identify the similarity postulate or theorem that applies.

Mathematics
1 answer:
Aleks [24]3 years ago
6 0

Answer:

Correct choice is  C. Similar AA.

Step-by-step explanation:

We have been given a picutre of the triangles. Using those information we need to find the correct choice.

Consider triangle FGH and triangle JKL.

∠F≅∠J  {Both are equal to 30°}

∠H≅∠L  {Both are equal to 50°}

Then triangle  FGH is similar to the triangle JKL by AA - similarity of the triangle. Because we are getting two congruent angle pairs.

Hence correct choice is  C. Similar AA.

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Mary is standing out on the balcony of her apartment which is 40 feet above the ground and looks up at a 31° angle to see her fr
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52 feet

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This situation can be represented by the attached figure as in the answer area.

Let M be the location of Mary.

Let S be the location of Sue.

Distance between apartments is given as 20 feet.

Distance between ground and balcony of Mary is 40 feet.

There is a right angled \triangle MOS.

\angle OMS = 31^\circ

To find:

The distance SO + 40 feet.

We can use tangent ratio here in right angled \triangle MOS.

tan\theta = \dfrac{Perpendicular}{Base}

tan31^\circ = \dfrac{SO}{MO}\\\Rightarrow tan31^\circ = \dfrac{SO}{20}\\\Rightarrow SO=20\times 0.6\\\Rightarrow \bold{SO=12\ ft}

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