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VLD [36.1K]
3 years ago
10

The length of a rectangle is 2 meters longer than the width. If the area is 30 square meters, find the rectangle's dimensions.

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
3 0
The answer would be 15
30 divided by 2
if it’s wrong I’m so sorry.
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A drawer has a volume of 1575 cubic inches. the drawer is 5 inches deep and 21 inches long. What is the width of the drawer?
katrin [286]
Volume is l × w × h
l = 21 in
h = 5 in
w = ?
volume = 1575 in

21 × 5 × w = 1575
105 × w = 1575
w = 1575 ÷ 105
w = 15 inches
3 0
3 years ago
NEEEEEEEDDDD HELPPPPPPP ASAPPPPPPPPP
Anni [7]

The true statement about the diagram is (a) IJ ≅ JG

<h3>How to determine the true statement?</h3>

From the question, we understand that:

KH bisects line IG at point J

This means that:

Line segment IG is divided into two equal parts, and point J is the middle

So, we have:

IJ ≅ JG

Hence, the true statement about the diagram is (a) IJ ≅ JG

Read more about perpendicular bisector at:

brainly.com/question/24753075

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8 0
2 years ago
On which number line do the letters represent -5 and +3?
Vika [28.1K]

Answer:

The first option

Step-by-step explanation:

3 0
3 years ago
Find the area of a regular decagon with an apothem of 5 meters and a side length of3.25 meter. Round to the nearest tenth
topjm [15]
We know that

<span>The regular decagon can be divided into 10 congruent triangles
</span>so
area regular decagon=10*[area of one triangle]

area triangle=b*h/2
where
b=3.25 m
h is the aphotem
h=5 m
area=3.25*5/2----> area=8.125 m²

area regular decagon=10*[8.125]----> 81.25 m²

Area=81.3 m²

the answer is
81.3 m²
6 0
3 years ago
The point (-7, 4) is reflected over the line x= -3. Then, the result point is reflected over the line y = x. Where is the point
Tema [17]

Answer: D. (4, 1)

Step-by-step explanation:

When we have a reflection over a line, the perpendicular distance to that line is invariant.

Then, if we have the point

(-7, 4) and we have a reflection over the line x = -3

The distance between the x component and the line is:

I -7 - (-3)I = 4

Then the reflected point will also be at a distance of 4 units to the line x = 3, and this is at the point x = 1.

Then the new point is (1, 4)

Now we do a reflection over the line x = y.

This type of reflection just changes the x-component by the y-component, and the y-component by the x-component.

Then the new point will be (4, 1)

Then the correct option is D.

6 0
2 years ago
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