The sum of the square of two consecutive even integers, the first of which is 2n

Mathematics

1 answer:

trasher [3.6K]3 years ago

6 0

Idk sorry im here just for fun

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Write b/bc in simplest form

inysia [295]

1/c I think thats what you needed

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4 years ago

Evaluate. 102+6⋅7+8 70142150190

Aloiza [94]

Hi.

102+6(7)+8 (your equation)
102+ 42+ 8 (since the order is PEMDAS, multiplication has to go first. 6x7=42
144 + 8 (since you go left to right, 102 +42 has to be 1st. Answer= 144)
152 (now the only thing left is 144 + 8, so do that. Answer= 152.)

Since that's the last step, 152 will be your answer.

Hoped I helped and if you need anymore you could always ask me~

-Dawn

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3 years ago

Read 2 more answers

Please help with this word problem!

Maru [420]

Answer:

first blank: c(x) = 45x + 14

second blank: 7

Step-by-step explanation:

explanation for second blank:

set up the equation equal to 329:

45x + 14 = 329

subtract 14 from both sides:

45x = 315

divide by 45 to leave x alone:

x = 7

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3 years ago

The CHS Baseball team was on the field and the batter popped the ball up. The equation b(x)=80t-16t^2+3.5 represents the height

Aleksandr [31]

Answer:

<em>t = 5 seconds</em>

Step-by-step explanation:

We must solve the equation of movement of the ball as a function of time in seconds.

We must find how many seconds it takes until the ball touches the ground. When the ball touches the ground, the height b (t) = 0

Then we equate the equation to zero and solve for t.

$80t-16t ^ 2 + 3.5 = 0$

Use the quadratic formula.

Where

$a = -16\\\\b = 80\\\\c = 3.5$

$t = \frac{-b \±\sqrt{b^2-4ac}}{2a}\\\\\\t_1 = \frac{-(80)-\sqrt{(80)^2-4(-16)(3.5)}}{2(-16)}\\\\t_1= 5.04\ s\\-------------------------\\t_2 =\frac{-(80)+\sqrt{(80)^2-4(-16)(3.5)}}{2(-16)}\\\\t_2=-0.0434\ s$