X^2+10x+21/x+3? If you meant (<span>x^2+10x+21)/(x+3), please note that those parentheses are essential.
If you wish to divide </span><span>x^2+10x+21 by (x+3) using synth. div., use the divisor -3:
_______________
-3 / 1 10 21
-3 -21
-----------------------
1 7 0
Since the remainder is 0, (x+3) is a divisor of </span><span>x^2+10x+21, and the other factor is (1x + 7).</span><span>
</span>
The answer is 0 because If two events are mutually exclusive, then the probability of either occurring is the sum of the
probabilities of each occurring.
Hope that Helps :)
The area of this regular polygon is 46.8 square units
<h3>How to determine the area of this
regular polygon?</h3>
The given parameters are:
Perimeter, p = 54 m
Apothem, a = √3
The area of this regular polygon is then calculated as:
Area = 0.5 * Apothem * Perimeter
Substitute the known values in the above equation
Area = 0.5 * √3 * 54
Evaluate the product
Area = 46.8
Hence, the area of this regular polygon is 46.8 square units
Read more about area at:
brainly.com/question/14137384
#SPJ1
