12345
+ 5.6742
12350.6742 kg
Answer:
The other length of the leg is <em>8 feet.</em>
Step-by-step explanation:
To find the answer we have to find what<em> 10</em> and <em>6 is squared.</em> <em>10 x 10 = 100</em>.
<em>6 x 6 = 36. </em>Now since we are trying to find the length of the other leg, we will <em>subtract 100 from 36</em> and we get <em>64</em>. Then for the last step, we will figure out what number<em> squared equals 64.</em> Because 8 x 8 = 64, <em>8 is our answer.</em>
Answer:
x= -4
Step-by-step explanation:
∠LMP + ∠PMN= 180° (adj. ∠s on a str. line)
-16x +13 -20x +23= 180
bring x term to 1 side, constant to the other:
-36x= 180 -13 -23
Simplify:
-36x= 144
x= 144 ÷ (-36)
x= -4
*The sum of the angles on a straight line is 180°
Well a<span>ll you have to do is turn one of the numbers from yards to feet or feet to yards, so you can accurately add it. Considering it would be easier to turn the yards to feet, you use the fact that, 1 yard is equal to 3 feet. So the 6 7/12 as feet is now 19.75 feet. So now you multiply them and 3 1/6 times 19.75 is 62.5416666535, and you can round this to just 63.</span>
Ok, so remember that the derivitive of the position function is the velocty function and the derivitive of the velocity function is the accceleration function
x(t) is the positon function
so just take the derivitive of 3t/π +cos(t) twice
first derivitive is 3/π-sin(t)
2nd derivitive is -cos(t)
a(t)=-cos(t)
on the interval [π/2,5π/2) where does -cos(t)=1? or where does cos(t)=-1?
at t=π
so now plug that in for t in the position function to find the position at time t=π
x(π)=3(π)/π+cos(π)
x(π)=3-1
x(π)=2
so the position is 2
ok, that graph is the first derivitive of f(x)
the function f(x) is increaseing when the slope is positive
it is concave up when the 2nd derivitive of f(x) is positive
we are given f'(x), the derivitive of f(x)
we want to find where it is increasing AND where it is concave down
it is increasing when the derivitive is positive, so just find where the graph is positive (that's about from -2 to 4)
it is concave down when the second derivitive (aka derivitive of the first derivitive aka slope of the first derivitive) is negative
where is the slope negative?
from about x=0 to x=2
and that's in our range of being increasing
so the interval is (0,2)
