Answer:
W=0.8333*t
2.917 ft³
Step-by-step explanation:
At time t=3, there is 2.5 ft³ of water in the tub
Finding the relation will be;
3=2.5
1=?
Rate=0.8333 ft³/min
W=0.8333 ft³ / min
W=0.8333*t
At t=3.5 will be;
1 min = 0.8333
3.5 min =?
Apply cross-production
3.5*0.8333 =2.917 ft³
Answer:
Step-by-step explanation:
Applying the Laplace transform:
![\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5By%27%27%5D%2B5%5Cmathcal%7BL%7D%5By%27%5D%2B4%5Cmathcal%7BL%7D%5By%27%5D%3D0)
With the formulas:
![\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5By%27%27%5D%3Ds%5E2%5Cmathcal%7BL%7D%5By%5D-y%280%29s-y%27%280%29)
![\mathcal{L}[y']=s\mathcal{L}[y]-y(0)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5By%27%5D%3Ds%5Cmathcal%7BL%7D%5By%5D-y%280%29)
![\mathcal{L}[x]=L](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5Bx%5D%3DL)
Solving for 
Apply the inverse Laplace transform with this formula:
![\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5E%7B-1%7D%5B%5Cfrac1%7Bs-a%7D%5D%3De%5E%7Bat%7D)
![y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}](https://tex.z-dn.net/?f=y%3D3%5Cmathcal%7BL%7D%5E%7B-1%7D%5B%5Cfrac1%7Bs%2B4%7D%5D%3D3e%5E%7B-4t%7D)
Answer:$1,929.20
Step-by-step explanation:First off, I noted that the answers are pretty far apart so I rounded up to $50 to make it simpler (you should only do this if the answers are pretty far apart from one another.)
$50 per day × 5 days per week × 8 weeks = $2,000. Closest answr (because I rounded) is $1,929.20.
Angle b= 50
Angle c= 130
Complementary angles are two angles that add to equal 90
Supplementary angles are two angles that add to equal 180
To find the measurement of angle b, subtract 40 from 90 (50)
To find the measurement of angle c, subtract 50 from 180 (130)
Given:
A data set has a median of 12, an upper quartile of 15, a lower quartile of 10, a minimum of 4, and a maximum of 20.
To find:
The correct statement for the box plot.
Solution:
Lower quartile is 10 and upper quartile is 15, so the box will go from 10 to 15.
Median of the data set is 12, so a line dividing the box will be at 12.
Minimum value is 4 and lower quartile is 10, so the left whisker will go from 4 to 10.
Upper quartile is 15 and maximum value is 20, so the right whisker will go from 15 to 20.
Therefore, the correct option is B.
