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UkoKoshka [18]
4 years ago
13

Calculate the volume of 1.00 x 10^-2M KOH solution containing 3.00 x 10^-1 mol of solute?

Chemistry
1 answer:
ioda4 years ago
7 0
Volume = ?

Molarity (M) = 1.00 x 10⁻² M

moles (n) = 3.00 x 10⁻¹ mol

V = n / M

V = 3.00 x 10⁻¹  / 1.00 x 10⁻²

V = 30 L
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<h3>Further explanation</h3>

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\large {\boxed {\bold {Ka \: = \: \frac {[H ^ +] [A ^ -]} {[HA]}}}}

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