1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lana66690 [7]
3 years ago
5

Which of the following pairs of elements is most likely to form an ionic compound? (Hint - question 4 tells you what types of el

ements to look for.)
A.) nitrogen (N) and sulfur (S)
B.) oxygen (O) and flourine (F)
sodium (Na) and chlorine (Cl)

Chemistry
1 answer:
mamaluj [8]3 years ago
3 0

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Ionic bonds.

Since Sodium (Na) is a cation and Chlorine (Cl) is a Anion, they both form a Ionic bond called as NaCl (common salt)

So answer is, Na and Cl

You might be interested in
True or false all countries are legally bound to survey and monitor for disease within their bodies
ra1l [238]

Answer:

False..........

7 0
2 years ago
A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 °C. What is the volume of the
alexdok [17]

Answer : The volume of the bubble is, 625 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 2.4 atm

P_2 = final pressure of gas = 1.0 atm

V_1 = initial volume of gas = 250 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 15^oC=273+15=288K

T_2 = final temperature of gas = 27^oC=273+27=300K

Now put all the given values in the above equation, we get:

\frac{2.4atm\times 250mL}{288K}=\frac{1.0atm\times V_2}{300K}

V_2=625mL

Therefore, the volume of the bubble is, 625 mL

7 0
2 years ago
Calculate the hydroxide ion concentration [OH-] for a solution with a pH of 6.10
nalin [4]

There are different formula you need to keep in mind when solving for [OH-]

Given that pH = 6.10

pH + pOH = 14

6.10 + pOH = 14

pOH = 7.9

[OH-] = 10^(-pOH)

[OH-] = 10^(-7.9)

[OH-] = 0.000000013

[OH-] = 1.3 x 10^-8


<h2><u>Answer: [OH-] = 1.3 x 10^-8</u></h2>
4 0
2 years ago
Identify the independent variable, dependent variable, and constant in the following problem: If you plant hydrangeas in your ga
Afina-wow [57]
The independent variable is the one you change, and the dependent variable is the one that changes because the independent changed (i think). The constant variable is the thing you can't change so the experiment is fair.

Independant: whatever causes the flowers to change color 
Dependent: the flowers change color
Constant: same soil type, same conditions, etc.
5 0
3 years ago
Read 2 more answers
one ball rolls along a shelf at a steady rate. a second ball rolls off the shelf and gains speed as it falls in a curved path. w
Salsk061 [2.6K]
The ball that rolls at a steady rate
6 0
3 years ago
Other questions:
  • Which of the following elements does NOT form a diatomic molecule?
    12·1 answer
  • A 155g sample of copper was heated to 150.0 degrees Celsius, then placed into 250.0g water at 19.8 degrees Celsius. Calculate th
    13·1 answer
  • A liter is the same as a _____.
    11·2 answers
  • The end product of the weathering of gabbros or basalt rocks is a solution of dissolved material that Mose likely would contains
    12·1 answer
  • Which statement about Niels Bohr’s atomic model is true?
    7·2 answers
  • The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wave
    9·1 answer
  • What's the Lewis dots for CCl4
    12·1 answer
  • How many grams of AICI: are needed to produce 150 grams of NaCl?
    12·1 answer
  • An element consists of 1.40% of an isotope
    14·2 answers
  • A concentration cell is constructed using two NI electrodes with Ni2 concentration of 1. 0 m and 1. 0 x 10^-4 m in the two half-
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!