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Nostrana [21]
3 years ago
13

Please help me due today i beg of u

Mathematics
2 answers:
Ray Of Light [21]3 years ago
6 0

Answer:

The top left one

Step-by-step explanation:

The line starts at 0

nasty-shy [4]3 years ago
4 0

Answer:

The first one (1)

Step-by-step explanation:

1                2

3               4

The numbers on the graph (just numbered them for better understanding)

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What number is 25 percent of 84?
raketka [301]

Answer: 21

Step-by-step explanation:25%=1/4

1/4*84 =84/4

84/4=21

3 0
3 years ago
Read 2 more answers
100 point reward with certified answer. 4 basic algebra questions, must show work. If the answers are wrong your response will b
ipn [44]
Y=kx
12=-4k
  k = -3

so when y = 15
y = kx
15 = -3x
  x = -5

----------------

$50 / 0.04 = $1250 (4% interest)

so
1250 * 0.06 = $75

answer
interest $75 at 6%

-----------------------------

y = kx
1/4 = 4k
k = 1/16

when x = 5
y = kx
y = 1/16(5)
y = 5/16 

-----------
y = kx
-5 = 4k
k = -5/4

direct equation
y = -5/4x

6 0
3 years ago
Find the value of x if it is a number between 8 and 12 exclusive.​
sergij07 [2.7K]

Given:

x is a number between 8 and 12 exclusive.​

To find:

The value of x.

Solution:

It is given that x is a number between 8 and 12 exclusive.​ It means the value of x lies between 8 and 12 but 8 and 12 are not included.

8

The whole numbers for 8 range are 9, 10, 11.

Therefore, the values of x are 9, 10, 11 and the value of x in the form of inequality is 8.

6 0
2 years ago
For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th
timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

(a,b)=\left \{ x\in\Re : a

2. Functions

1) \Re \rightarrow \Re \\ f(x)=x

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2)\Re\geq0\rightarrow\Re , f(x)=x+1\\

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3)f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)

The cosine function is not injective, bijective nor surjective.

4)f:\Re\rightarrow\Re \:f(x)=ex

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5)  Quite unclear format

6) \:f:\Re\rightarrow(0,\infty), f(x) =ex

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

7) f:\Re\geq 0 \rightarrow  \Re\geq0, f(x) =x^{4}

Not injective nor surjective therefore not bijective too.

8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}

f(-1)=1, f(2)=4, f(-3)=9

Injective (one to one), Surjective,  and Bijective.

10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.

Surjective.

11.f:R\geq 0[-1,1], f(x) = 0\\

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

7 0
2 years ago
Decide if the relationship described by the table of values is a function or not.​
gizmo_the_mogwai [7]

Answer:

Yes

Step-by-step explanation:

A function is a function when each domain is paired with exactly 1 range. So, this also means that there can't be a domain with more than 1 of the same number. Meaning 2 3's or 4 2's.

3 0
3 years ago
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