All categories

2 years ago

What could you do to make the inequalities that are not true into true statements

Mathematics

1 answer:

iren2701 [21]2 years ago

6 0

Answer:

example, if both sides of the inequality are multiplied by a negative number, say -3, we get (-2) x (-3) < 7 x (-3) 6 < -21 When both sides of the inequality are multiplied by a negative number, the resulting inequality is not true. To make the resulting inequality true, we have to reverse the inequality symbol.

Step-by-step explanation:

You might be interested in

What is a solution set?

andreev551 [17]

Set of ordered pairs that make an equation true.

6 0

3 years ago

Find the values of x and y in the figure below. Enter the answers as numbers.

ella [17]

Answer: $x=79^{\circ}\ and\ y=101^{\circ}$

Step-by-step explanation:

In the given picture, a parallelogram PQRS is given with angle 101°.

In a parallelogram opposite angles are equal.

Since, y is opposite to 101°.

Therefore y=101°

Also, the sum of the adjacent angles of a parallelogram is 180°

$\\\Rightarrow\ x+101^{\circ}=180^{\circ}\\\Rightarrow\ x=180^{\circ}-101^{\circ}\\\Rightarrow\ x=79^{\circ}$

8 0

3 years ago

Consider a convex hexagon in which all pairs of opposite sides are parallel. Prove that if one pair of opposite sides have equal

hjlf

A pair of the opposite sides of a hexagon has equal length and this is proved below.

<h3>How to illustrate the hexagon?</h3>

It should be noted that a hexagon is a polygon that has six sides.

In this case, it has 6 sides.

The total angles will be:

= (n - 2) × 180

= (6 - 2) × 180

= 720°

Each angle will hence be:

= 720°/6

= 120°

Each angle are equal and this illustrates that the parallel sides are equal.

A diagram is attached to illustrate the pair of parallel sides.

Learn more about hexagon on:

brainly.com/question/1615720

#SPJ1

6 0

2 years ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$