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Andre45 [30]
3 years ago
14

Simplify and Explain Sum: -7 + 9 - 3 * 6 -(5 + 9) ÷ 7

Mathematics
1 answer:
Makovka662 [10]3 years ago
8 0

Answer:

-18

Step-by-step explanation:

Multiply the numbers

3*6

-7 + 9 - 18 - (5 + 9) ÷ 7

Add the numbers

5+9

-7 + 9 - 18 - 14 ÷ 7

Divide the numbers

14÷ 7

-7 + 9 - 18 - 2

Calculate the sum or difference

-18

Answer = -18

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The number 15, 56 rounded to the nearest thousand is 15,000. Which numbers could be the missing digit?
Virty [35]

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4 0
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In the following questions, look at different ways to represent the relation given by the equation y = x2 - 1. The table below s
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Answer:

a= 3

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Step-by-step explanation:

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2 years ago
The tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds. If 50,000 part
nalin [4]

Answer:

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

7933 parts

b) How many would have a tensile strength in excess of 48 pounds?

2739.95 parts

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

Determining the Probability value from Z-Table:

P(x<35) = 0.15866

Converting to percentage = 15.866%

We are asked how many will fail to meet this specification

We have 50,000 parts

Hence,

15.866% of 50,000 parts will fail to meet the specification

= 15.866% of 50,000

= 7933 parts

Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

P-value from Z-Table:

P(x<48) = 0.9452

P(x>48) = 1 - P(x<48)

1 - 0.9452

= 0.054799

Converting to percentage

= 5.4799%

Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

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3 years ago
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S_A_V [24]
4 times (x^2-9x+8). Hope that helps!
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