This is true do to all the other particules around
Answer: Time required to deposit an even layer of gold with given thickness is
sec.
Explanation:
The given data is as follows.
Surface area = 49.8
,
Density of gold = 19.3
,
Current = 3.15 A, thickness of gold layer = 
It is known that relation between volume, area and thickness is as follows.
V = Surface area × Thickness
= 
= 0.05988 
Therefore, we will calculate the time required to deposit an even layer of gold with given thickness is calculated as follows.

=
sec
Thus, we can conclude that time required to deposit an even layer of gold with given thickness is
sec.
6.9 x 10 to the power of 3 if I am not mistaken.
<em>The cathode is Y</em>
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Further explanation</em></h3>
Electrolysis uses electrical energy to carry out redox reactions that are not spontaneous.
The ions in the solution flowing electrically will move towards to opposite charge of the electrode
The electrolysis material is an electrolyte which can be a solution or a melt.
In positive pole electrolysis cells - the anode is the site of the oxidation reaction, while the negative pole - the cathode is the reduction reaction site.
The result of the reaction in the anode is based on a substance that easily oxidized while the reaction in the cathode is based on a substance that easily reduced.
Electrons (electricity) enter an electrolysis cell through the negative pole (cathode)
The negative ion from the solution will move towards the positive electrode and release the electrons around the positive electrode (oxidation) and the electrons flow to the negative pole
Whereas around the negative electrode, there is electron binding and a reduction reaction occurs
So if we see the picture the cathode is Y
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Learn more</em></h3><h3><em>
reaction related to electrochemistry brainly.com/question/3461108</em></h3>
<h3><em>
Answer details </em></h3>
Grade: Senior High School
Subject: Chemistry
Chapter: Electrochemistry
Keywords: cathode, anode, oxidation, reduction, negative pole, electrode
The answer to this question is 8735.1