Calculate the heat (in calories) released when 115 g of CHCl3 changes from a liquid to a solid at

1 answer:

4 0

Answer: 8855 Joules energy is released when 115 g of $CHCl_3$ changes from a liquid to a solid at its freezing point.

Explanation:

Latent heat of freezing is the amount of heat released to convert 1 mole of liquid to solid at atmospheric pressure.

Amount of heat released to freeze 1 gram of $CHCl_3$ = 77 J/g

Mass of $CHCl_3$ given = 115 gram

Heat released when 1 g of $CHCl_3$ is freezed = 77 J

Thus Heat released when 115 g of $CHCl_3$ is freezed = $\frac{77}{1}\times 115=8855J$

Thus 8855 Joules energy is released when 115 g of $CHCl_3$ changes from a liquid to a solid at its freezing point.

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