Question

A study was done to compare people's religion with how many days that they have said they have been calm in the past three days. 0 days 1 day 2 days 3 days Protestant 50 27 6 16 Catholic 55 19 2 11 Jewish 84 34 4 18 Other 84 34 2 22 What proportion of Protestants were calm for 2 out of the 3 days? NOTE: Read the question very carefully.

Answer 1

Answer:

The probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.

Step-by-step explanation:

Represent the provided data as follows:

Compute the probability of the number of Protestants that were calm for 2 out of 3 days as follows:

$P (Calm\ for\ 2\ days\ |\ Protestants) = \frac{n (Protestants\ who\ were\ calm\ for\ 2\ days}{n (Protestants}$

The number of Protestants surveyed is, n (Protestants) = 99.

The number of Protestants who were calm for 2 days,

n (Protestants who were calm for 2 days) = 6

The required probability is:

$P (Calm\ for\ 2\ days\ |\ Protestants) = \frac{n (Protestants\ who\ were\ calm\ for\ 2\ days}{n (Protestants}\\=\frac{6}{99}\\ =0.060606\\\approx0.061$

Thus, the probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.