4,680 I do it like this 50 percent is 3600 then 10 percent is 720 and 5 percent is 360 add then you get 4,680
Answer: see below
<u>Step-by-step explanation:</u>
C(x) = 39 when 0 < x ≤ 1.0
C(x) = 63 when 1.0 < x ≤ 2.0
C(x) = 87 when 2.0 < x ≤ 3.0
C(x) = 111 when 3.0 < x ≤ 4.0
C(x) = 135 when 4.0 < x ≤ 5.0
C(x) = 159 when 5.0 < x ≤ 6.0
Based on the information I provided above, the answers are:
a) x= 0.6, C(x) = 1.0
x = 1.0, C(x) = 39
x = 1.1, C(x) = 63
x = 2.5, C(x) = 87
x = 3.0, C(x) = 87
x = 4.8, C(x) = 135
x = 5.0, C(x) = 135
x = 5.3, C(x) = 159
b) If C(x) = 87, then 2.0 < x ≤ 3.0
c) Domain (all possible x-values): 0 < x ≤ 6.0
d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}
Answer:
27.8
Step-by-step explanation:
You need to do brackets first
3.6-1.8 = 1.8
Then substitute
4.5 x 8- (0.4 + 9.6- 1.8)
0.4+9.6-1.8=8.2
4.5 x 8 - 8.2 =27.8
Answer:
Both angles have a measure of 134degrees, y = 27degrees.
Step-by-step explanation:
As per what is given in the problem:
There are 2 parallel lines, both are intersected by a transversal.
Remember the theorem, when two parallel lines are intersected by a transversal, then the alternate exterior angles are congruent.
The is meanse that:
3y + 53 = 7y - 55
Solve using inverse operations:
3y + 53 = 7y - 55
+55 +55
3y + 108 = 7y
-3y -3y
108 = 4y
/4 /4
27 = y
Now, substitute back in to find the value of the angle:
3y + 53
y = 27
3 ( 27 ) + 53
81 + 53
= 134
Since the angles are alternate exterior, they are congruent, hence both angles have a measure of 134degrees.
