Hello
<span>an equation for the line in point-slope form and general form is :
y = ax+b a : </span>slope ; the <span>Passing through (x' ; y')
</span>y' = ax'+b
y-y' =a(x-x') and : x' =2 y' = - 1
calculate a :
let : y = ax+b .....(D)
....<span>3y-x=7</span>....(D') or y = (1/3)x+7/3
.(D) perpendicular to(D') : slope (D) × slope (D') = -1
slope (D') = 1/3
slop(D)×(1/3) = -1
slope (D) = -3
equation for the line : y-y' =a(x-x')
y+1 =(-3) (x-2)
Hope this helps. It has the y and x intercepts on the graph.
Answer:
\frac{15a+20b}{6} 15a+20b/6
Step-by-step explanation:
\mathrm{Apply\:the\:fraction\:rule}:\quad \:a\cdot \frac{b}{c}=\frac{a\cdot \:b}{c}
Answer: -1/2
Step-by-step explanation:
Slope=rise/run
Up 1 and to the left 2 which makes it a negative
