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jeka94
3 years ago
12

For which equation is (4, 3) a solution?

Mathematics
2 answers:
Alex73 [517]3 years ago
6 0

Answer:

y = 2x - 5

Step-by-step explanation:

y = 2x - 1

3 = 2(4) - 1

3 = 8 - 1

3 ≠ 7

y = 3x - 4

3 = 3(4) - 4

3 = 12 - 4

3 ≠ 8

y = 2x - 5

3 = 2(4) - 5

3 = 8 - 5

3 = 3

y = x + 3

3 = 4 + 3

3 ≠ 7

Zepler [3.9K]3 years ago
3 0

Answer:

The answer is the third one y=2x-5

솓 묹ㄷㄱ ㅑㄴ 솓 소ㅑㄱㅇ ㅐㅜㄷ ㅛ=2ㅌ-5

Step-by-step explanation:

hope this helped!!!

ㅙㅔㄷ 소ㅑㄴ ㅗ디ㅔㄷㅇ!!!

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Step-by-step explanation:

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8 0
2 years ago
Read 2 more answers
Help..........................
kogti [31]

Answer:

D

Step-by-step explanation:

I'm not certain but I guess that's it

5 0
2 years ago
A total of 75 cookies and cakes were donated for a bake sale to raise money for the football team. There were four times as many
MArishka [77]

Answer:

60

Step-by-step explanation:

15*4 = 60

15+60= 75

6 0
3 years ago
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Use the given graph. Determine the period of the function.
Ivahew [28]

Answer:

3

Step-by-step explanation:

Period of a function is the period after which the function attains the same value

in the graph attached with this problem we can see that

f(0)=1

the value of x for which function f(x) attains the value 1 again is at

x=3

f(3)=1

similarly , we see

f(6)=1 , f(9)=1

Hence we see that after every increased value of x by 3 units , we attain the same value of function . hence the period of the function is 3

6 0
3 years ago
7 1/6 = 5 2/5 + p<br><br> p = ???
Crank

\huge\textbf{Hey there!}

\mathbf{7\dfrac{1}{6} = 5\dfrac{2}{5} + p}

\rightarrow\mathbf{7 \dfrac{1}{6} = 5\dfrac{2}{5} + p}

\mathbf{\rightarrow p + 5\dfrac{2}{5}= 7\dfrac{1}{6}}

\mathbf{\rightarrow {p + \dfrac{27}{5}=\dfrac{43}{6}}}

\text{SUBTRACT }\rm{\dfrac{27}{5}}\text{ to BOTH SIDES}

\mathbf{p + \dfrac{27}{5} - \dfrac{27}{5} = \dfrac{43}{6}- \dfrac{27}{5}}

\text{CANCEL out: }\rm{\dfrac{27}{5} - \dfrac{27}{5}}\text{ because it gives you 0}

\text{KEEP: }\rm{\dfrac{43}{6} - \dfrac{27}{5}}\text{ because it help solve for the p-value}

\text{NEW EQUATION: }\rm{p = \dfrac{43}{6} - \dfrac{27}{5}}

\large\textsf{SIMPLIFY IT!}

\mathbf{p = \dfrac{53}{30} \approx p = 1\dfrac{23}{30}}

\huge\boxed{\textsf{Therefore, your answer is: \boxed{\mathsf{p = 1\dfrac{23}{30}}}}}\huge\checkmark

\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}

~\frak{Amphitrite1040:)}

3 0
2 years ago
Read 2 more answers
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