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Travka [436]
3 years ago
5

11 + (-3)+(-5) =10•-5-42÷ ​

Mathematics
1 answer:
8_murik_8 [283]3 years ago
4 0

Answer: 3=-50

Step-by-step explanation:

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In order to maintain a healthy weight, an average adult dog that weighs 20 kilograms must consume 11 grams of dog food per kilog
masha68 [24]
2 cups of dog food is 194 grams and 3 cups is 291 grams.
The dog needs 220 grams. So at most 3 cups of dog food. Wish I could simplify more but I can't. sorry.
6 0
3 years ago
Traders joes sold 7981 bags of tortilla chips recently. If 1178 of these bags were fat free find the percent that were fat free.
lawyer [7]

Answer:

14.76% of tortilla chips bag were fat free.  

Step-by-step explanation:

We are given the following in he question:

Number of bags of tortilla chips sold = 7981

Number of bags hat were fat free = 1178

We have to find the percentage of bags that were fat free.

Percentage:

\dfrac{\text{Number of fat free bags}}{\text{Total number of bags}}\times 100\%\\\\=\dfrac{1178}{7981}\times 100\%\\\\=14.76\%

Thus, 14.76% of tortilla chips bag were fat free.

4 0
3 years ago
Please help me I will give you the brain thing and extra points. (image below) 21/30
fomenos
I think it would maybe be 35 or 45.
7 0
3 years ago
Read 2 more answers
11/6358 long agurithum
miss Akunina [59]

Answer:

Least common multiple:

lcm (578; 11) = 6,358 = 2 × 11 × 172;

Numbers have no common prime factors: 6,358 = 578 × 11.

Step-by-step explanation:

Approach 1. Integer numbers prime factorization:

578 = 2 × 172;

11 is a prime number, it cannot be broken down to other prime factors;

Multiply all the prime factors, by the largest exponents.

Least common multiple:

lcm (578; 11) = 2 × 11 × 172;

lcm (578; 11) = 2 × 11 × 172 = 6,358

Numbers have no common prime factors: 6,358 = 578 × 11.

Integer numbers prime factorization

Approach 2. Euclid's algorithm:

Calculate the greatest (highest) common factor (divisor), gcf, hcf, gcd:

Step 1. Divide the larger number by the smaller one:

578 ÷ 11 = 52 + 6; Step 2. Divide the smaller number by the above operation's remainder:

11 ÷ 6 = 1 + 5; Step 3. Divide the remainder from the step 1 by the remainder from the step 2:

6 ÷ 5 = 1 + 1; Step 4. Divide the remainder from the step 2 by the remainder from the step 3:

5 ÷ 1 = 5 + 0; At this step, the remainder is zero, so we stop:

1 is the number we were looking for, the last remainder that is not zero.

This is the greatest common factor (divisor).

Least common multiple, formula:

lcm (a; b) = (a × b) / gcf, hcf, gcd (a; b);

lcm (578; 11) =

(578 × 11) / gcf, hcf, gcd (578; 11) =

6,358 / 1 =

6,358;

lcm (578; 11) = 6,358 = 2 × 11 × 172;

8 0
3 years ago
Find the sum of the first 5,000 odd numbers
Nata [24]

Step-by-step explanation:

this is an arithmetic sequence :

a1 = 1

an = an-1 + 2 = a1 + (n-1)×2

the sum of n terms of an arithmetic sequence is

S = n×(a1 + an)/2

n = 5000

an = a1 + 4999×2 = 9999

S = 5000×(1 + 9999)/2 = 5000×5000 = 25,000,000

4 0
2 years ago
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