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igor_vitrenko [27]
3 years ago
8

Write the smallest 4-digit numeral using 0,2,8, and 7

Mathematics
1 answer:
Sholpan [36]3 years ago
7 0
Should be 0,2,7,8 i dont think you could go any lower
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R varies directly as s. Find r when s=10 and k=4
nadezda [96]

Step-by-step explanation:

Since, r varies directly as s

\therefore \: r \:  \:  \alpha \:  \: s \\  \therefore \: r  = k s..(1) \:  \\ (k =  \: constant \: of \: proportionality ) \\ plug \: s = 10 \: and \: k = 4 \:  in \: equation \: (1) \\ r = 4 \times 10 \\ \huge \red{ \boxed{ \therefore \: r  =40}}

5 0
3 years ago
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A top is on sale for 30% off. If the top was originally $18.50, what is the sale
bearhunter [10]

Answer:

it will be $12.6 dollars

Step-by-step explanation:

5 0
3 years ago
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Find a recursive formula for the sequence:<br><br> 1, -1, -7, -25
Mumz [18]
<h3>Answer:</h3>

a_n=3a_{n-1}-4

<h3>Step-by-step explanation:</h3>

<em>Try the answers</em>

You can try the answers to see what works. You can expect all of the choices to match the first two terms, so try some farther down. Let's see if we can get -25 from -7.

a) 3*(-7) -4 = -21 -4 = -25 . . . . this one works

b) -7 -2 = -9 . . . . ≠ -25

c) -3(-7) +2 = 21 +2 = 23 . . . . ≠ -25

d) -2(-7) +1 = 14 +1 = 15 . . . . ≠ -25

The formula that works is the first one.

_____

<em>Derive it</em>

All these formulas depend on the previous term only, so we can write equations that show the required relationships. Let the unknown coefficients in our recursion formula be p and q, as in ...

a_n=p\cdot a_{n-1}+q

Then, to get the second term from the first, we have

... 1·p +q = -1

And to get the third term from the second, we have

... -1·p +q = -7

Subtracting the second equation from the first gives ...

... 2p = 6

... p = 3 . . . . . . . this is sufficient to identify the first answer as correct

We can find q from the first equation.

... q = -1 -p = -1 -3 = -4

So, our recursion relation is ...

a_n=3a_{n-1}-4

6 0
3 years ago
If y=kx, where k is a constant, and y=24 when x=6, what is the value of y when x=5
Phoenix [80]
I hope this helps <span>24 = k * 6  </span><span>4 = k  </span><span>y = kx  </span><span>y = 4x  </span><span>y = 4 * 5  </span><span>y = 20 

</span>
6 0
3 years ago
Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th
xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

Thus replacing the functions of the exercise we get:

W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0
3 years ago
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