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3 years ago

3x-5=x+1 Helpppppppppppp

2 answers:

7 0

First you subtract 3x-x since they are like terms turning the equation into 2x-5=1. Then you add 5+1 because they are like terms making the equation 2x=6. Last you divide 6/2 to get x=3

Vikentia [17]3 years ago

4 0

Answer:

your answer is x= 3

Hope this helps!

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11.(02.03)

Marianna [84]

Answer:

step number 1 is incorrect.

Step-by-step explanation:

Here is the solution of this equation [2x-31-1=2].

2x-31-1=2

or 2x-31=2+1

or 2x=2+1+31

or 2x= 34

or x=34/2

or x= 17

the answer of this equation is X=17.

8 0

3 years ago

Can someone answer this i am in forth grade 7/8 x 3 =

Korvikt [17]

The answer is 2/6 :)

6 0

3 years ago

The equation for line r can be written as y=-1/4x+3. Line s which is parallel to lone r includes the point (-4,3). What is the e

MaRussiya [10]

Answer:

$y=-\frac{1}{4}x+2$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0)
Parallel lines always have the same slope

1) Determine the slope of line S using line R (m)

$y=-\frac{1}{4} x+3$

We can identify clearly that the slope of the line is $-\frac{1}{4}$ , as it is in the place of m. Because parallel lines always have the same slope, the slope of line S would also be $-\frac{1}{4}$ . Plug this into $y=mx+b$ :

$y=-\frac{1}{4}x+b$

2) Determine the y-intercept of line S (b)

$y=-\frac{1}{4}x+b$

Plug in the given point (-4,3) and solve for b

$3=-\frac{1}{4}(-4)+b\\3=1+b$

Subtract 1 from both sides to isolate b

$3-1=1+b-1\\2=b$

Therefore, the y-intercept is 2. Plug this back into $y=-\frac{1}{4}x+b$ :

$y=-\frac{1}{4}x+2$

I hope this helps!

6 0

3 years ago

X - x-2/6 = x-7/3 + 2/3

elena-s [515]

X-x-2/6=x-7/3+2/3
-2/6+7/3-2/3=x
x= -2/6+5/3
x= 8/6
x= 4/3

3 0

3 years ago

Some researchers have conjectured that stem-pitting disease in peach-tree seedlings might be controlled with weed and soil treat

stiks02 [169]

Answer:

Part A

b. 14.6 ± 7.38

Part B

b. 3.43

Part C

a. P-value < 0.01

Part D

b. There is sufficient evidence to reject the null hypothesis

Step-by-step explanation:

Part A

The given data are;

The number of seedlings in the field = 20

The number of seedlings selected to receive herbicide A = 10

The number of seedlings selected to receive herbicide B = 10

The height in centimeters of seedlings treated with Herbicide A, $\overline x _1$ = 94.5 cm

The standard deviation, s₁ = 10 cm

The height in centimeters of seedlings treated with Herbicide B, $\overline x _2$ = 109.1 cm

The standard deviation, s₂ = 9 cm

The 90% confidence interval for μ₂ - μ₁, is given as follows;

$\left (\bar{x}_{2}- \bar{x}_{1} \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}$

The critical-t at 95% and n₁ + n₂ - 2 degrees of freedom is given as follows;

The degrees of freedom, df = n₁ + n₂ - 2 = 10 + 10 - 2 = 18

α = 100% - 90% = 10%

∴ For two tailed test, we have, α/2 = 10%/2 = 5% = 0.05

$t_{(0.025, \, 18)}$ = 1.734

$C.I. = \left (109.1- 94.5 \right )\pm 1.734 \times \sqrt{\dfrac{10^{2}}{10}+\dfrac{9^{2}}{10}}$

C.I. ≈ 14.6 ± 7.37714603353

The 90% C.I. ≈ 14.6 ± 7.38

b. 14.6 ± 7.38

Part B

With the hypotheses are given as follows;

H₀; μ₂ - μ₁ = 0

Hₐ; μ₂ - μ₁ ≠ 0

The two sample t-statistic is given as follows;

$t=\dfrac{(\bar{x}_{2}-\bar{x}_{1})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}+\dfrac{s _{2}^{2}}{n_{2}}}}$

$t-statistic=\dfrac{(109.1-94.5)}{\sqrt{\dfrac{10^{2} }{10}+\dfrac{9^{2}}{10}}} \approx 3.43173361147$

The two sample t-statistic ≈ 3.43

b. 3.43

Part C

From the t-table, the p-value, we have, the p-value < 0.01

a. P-value < 0.01

Part D

Given that a significance level of 0.05 level is used and the p-value of 0.01 is less than the significance level, there is enough statistical evidence to reject the null hypothesis

b. There is sufficient evidence to reject the null hypothesis.

4 0

3 years ago