So, givens: total lesson cost of $260, total lessons taken are 6, and the first lesson costs 1.5 (or 3/2) as much as the additional lessons.
First thing to do is to figure out how many additional lessons are in that, which are 5.
Then you can make a 1 variable equation with the information you have. I’m using x as my variable.
260= 3/2x + 5x
Combine like terms.
260 = 13/2x
Divide both sides by 13/2 (treat it as a fraction, and if your calculator cannot make fractions, then decimal might help for this. 13/2=6.5)
X=40
Very interesting question!
Let's try to get something that would work for just 5 for now.
Any of these numbers would leave a remainder of 1 when divided by just 5:
6, 11, 16, 21, 26, 31, 36, 41, 46, 51, 56, 61, 66, 71, 76, 81, 86, ...
Notice that they all look like 5*(something) + 1. Basically, they are all multiples of 5 plus 1.
Let's see what would work for just 8:
9, 17, 25, 33, 41, 49, 57, 65, 73, 81, 89, ...
Are there any matches... AHA! It's 81. This is the lowest positive integer greater than 1 that follows the rule for both 5 and 8.
Answer:
157 boxes
Step-by-step explanation:
Take the total amount of ounces to be made, and divide by the 'size' of the box. with 7,536 ounces to be made and the boxes being 48 ounces: 7536/48 will equal 157 boxes filled.
Answer:
f(x) = 
Step-by-step explanation:
All you have to do is multiply (x + 1)(x + 2)(x - 4)
You should get
So, f(x) =
Answer:
( x - 2 )^2 + ( y - 1 )^2 = 1
Step-by-step explanation:
As i previously explained,
The general form of equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2.
h and k are the co-ordinates of the center of circle and r is the radius
Here, We have (2,1) as the co-ordinates of the center of circle
Now,
( x - h )^2 + ( y - k )^2 = r^2
or,( x - 2 )^2 + ( y - 1 )^2 = r^2
The radius of the circle is 1 units(from figure)
So, put that in, we get
( x - 2 )^2 + ( y - 1 )^2 = 1^2
or, ( x - 2 )^2 + ( y - 1 )^2 = 1
You can simplify this or leave it here.
